Proving an entire function is a polynomial under certain conditions

In summary, the conversation discusses how to prove that an entire function with a certain growth condition is a polynomial of degree less than or equal to n. Hints are given, including using the power series expansion and Cauchy's integral formula. The key idea is to show that the higher derivatives of f are bounded on the whole plane, which implies that f is a polynomial of degree less than or equal to n.
  • #1
Bingk1
16
0
Hello,
This was an exam question which I wasn't sure how to solve:

Suppose [TEX]f[/TEX] is entire and [TEX]|f(z)| \leq C(1+ |z|)^n[/TEX] for all [TEX]z \in \mathbb{C}[/TEX] and for some [TEX]n \in \mathbb{N}[/TEX].
Prove that [TEX]f[/TEX] is a polynomial of degree less than or equal to [TEX]n[/TEX].

I know that f can be expressed as a power series, but I'm not sure how to show that the upper limit of the sum has to be less than or equal to n.

Thanks!
 
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  • #2
Hints:

  • $f^{(n)}(z)$ is entire for all $n\in{\mathbb{N}}$.
  • $\frac{1}{2\pi\cdot i}\cdot \oint_\Gamma \frac{f(z)}{(z-w)^{n+1}}dz = \frac{f^{(n)}(w)}{n!}$ where $\Gamma$ is, say, a circle centered at $w$ of radius $R$.
  • What can you say, then, about $f^{(n)}(w)$ for some $n$ ? (Hint: try to find a uniform bound for $f^{(n)}(w)$ on the whole plane)
 

FAQ: Proving an entire function is a polynomial under certain conditions

What is an entire function?

An entire function is a complex-valued function that is defined and analytic over the entire complex plane. This means that the function is differentiable at every point in the complex plane.

What does it mean for an entire function to be a polynomial?

An entire function is a polynomial if it can be written as a finite sum of powers of the independent variable, with complex coefficients. In other words, the function is a polynomial if it can be expressed in the form f(z) = anzn + an-1zn-1 + ... + a0, where n is a non-negative integer and an, ..., a0 are complex numbers.

What are the conditions for proving an entire function is a polynomial?

The conditions for proving an entire function is a polynomial vary depending on the specific problem. However, in general, some common conditions include showing that the function is bounded, that it satisfies Cauchy's integral formula, or that it has a finite number of zeros.

Can an entire function be a polynomial of infinite degree?

No, an entire function cannot be a polynomial of infinite degree. This is because, by definition, a polynomial is a finite sum of powers of the independent variable. Therefore, an entire function must have a finite degree if it is a polynomial.

Why is it important to prove that an entire function is a polynomial?

Proving that an entire function is a polynomial can provide valuable insights into the behavior and properties of the function. It can also help solve complex mathematical problems and lead to a better understanding of the underlying principles of complex analysis. Additionally, proving an entire function is a polynomial can have practical applications in fields such as physics, engineering, and economics.

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