Proving Continuity of a Function at an Isolated Point

In summary, the conversation discusses the proof that a point xo in a given domain is either an isolated point or a limit point of the domain. The first part of the conversation focuses on the definition of an isolated point and its relationship to limit points. The second part presents a similar problem and discusses the continuity of a function at an isolated point. The solution shows that for any small epsilon value, there exists a corresponding delta value such that the function is continuous at xo.
  • #1
xsw001
37
0
[a]1. Homework Statement [/a]

Prove that a point xo in Domain is either an isolated point or a limit point of D.

[a]2. Homework Equations [/a]

xo in D is an isolated point provided that there is an r>0 such that the only point of domain in the interval (xo-r, xo+r) is xo itself.

[a]3. The Attempt at a Solution [/a]

Is there any other possibility if D={xo}, then xo is is certinaly not a limit point since single point of a set has no limit point, then it must be isolated point?

Another similar problem

Homework Statement


Suppose xo is an isolated point of D.
Prove that every function f:D->R is continuous at xo.

Homework Equations



xo in D is an isolated point provided that there is an r>0 such that the only point of domain in the interval (xo-r, xo+r) is xo itself.

Isolated point is NOT a limit point.

The Attempt at a Solution



Show for all epsilon>0, there exists a delta>0 such that if |x-xo|<delta, then |f(x)-f(xo)|<epsilon?

so I can just let r=delta isn't it?
so for every epsilon>0, there exists a delta=r>0 such that |x-xo|<r=delta, then |f(x)-f(xo)|<epsilon?
 
Last edited:
Physics news on Phys.org
  • #2
Since xo is an isolated point, r>0 such that the only point of domain in the interval (xo-r, xo+r) is xo itself.This means that for any x such that |x-xo|<r, x=xo and since f is function, it's constant at xo which implies that |f(x)-f(xo)|=0<epsilon. Therefore, f is continuous at xo.
 

FAQ: Proving Continuity of a Function at an Isolated Point

What is continuity of a function at an isolated point?

Continuity at an isolated point means that a function has a defined value at that point and its limit approaches that value as the independent variable approaches the isolated point.

How do you prove continuity at an isolated point?

To prove continuity at an isolated point, you need to show that the limit of the function as x approaches the point is equal to the function's value at that point. This can be done using the epsilon-delta definition of a limit or by using the continuity theorem.

What is the continuity theorem?

The continuity theorem states that if a function is continuous on an interval (a,b) and has a limit at a particular point c, then the function is also continuous at that point c.

What is the epsilon-delta definition of a limit?

The epsilon-delta definition of a limit is a mathematical method for proving that a function has a limit at a particular point. It involves finding a value for delta (δ) such that when x is within a distance of delta from the point c, the function's value is within a distance of epsilon (ε) from the limit L.

What are some common examples of functions with isolated points?

Some common examples of functions with isolated points include piecewise functions, functions with removable discontinuities, and functions with jump discontinuities.

Similar threads

Replies
4
Views
2K
Replies
3
Views
2K
Replies
2
Views
688
Replies
5
Views
7K
Replies
12
Views
20K
Replies
11
Views
716
Back
Top