Proving convergence of factorial w/o Ratio Test

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The discussion focuses on determining the convergence of the series 1/n! using comparison tests. Participants suggest using limit comparison with simpler series, emphasizing that for large n, n! grows faster than n^2 and 2^(n-1). The importance of the Comparison Test is highlighted, noting that if n! is greater than n^2 for sufficiently large n, the reciprocal series will converge. Acknowledgment of a common typo regarding the relationship between 2^n and n! is made, reinforcing the need for careful analysis. Ultimately, the convergence of 1/n! can be established through these comparisons.
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Homework Statement


Determine whether 1/n! diverges or converges.
So far, we have only learned the comparison tests, p-series, geometric series, divergence test, and integral test, so I can only use these tests to prove it.


Homework Equations



N/a

The Attempt at a Solution



I thought about using limit comparison with my b_n=1/n^n, but I can't determine if that converges or not, so I don't know what to do.
 
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Why did you choose b_n = 1/n^n? Why not a simpler series that you know converges or diverges?
 
The Comparison Test is your friend
 
It should be clear that for n> 3, n^2> n!.
 
HallsofIvy said:
It should be clear that for n> 3, n^2> n!.

I think you meant 2^n < n! ? Easy typo to make.

Oops, it's 2^(n-1) < n!
 
It's monotonic, so if you show that it is bounded, you're in business. Now by the comparison test, we have n!>n^2 for sufficiently large n, so take reciprocals and go from there.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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