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dmac1215
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I have a super round about way to prove this, but I'm having trouble finding a succinct proof
Let (tn) be diverge and (sn) converge. Show (tn+sn) diverges
The way I was doing involved considering that tn was unbounded, then showing it (sn+tn) is divergent.
Then I had to consider that tn is bounded and oscillatory, consider convergent subsequences, and show (sn+tn) had no unique limit, and therefore diverges. This part of the proof seemed less clear and I'm not sure if I can assert that because I have convergent subsequences of (tn) with multiple limits that (sn+tn) also has multiple limits.
I figure there has got to be some simple contradiction proof involving some triangle inequality trick that I'm just missing.
Thanks
Let (tn) be diverge and (sn) converge. Show (tn+sn) diverges
The way I was doing involved considering that tn was unbounded, then showing it (sn+tn) is divergent.
Then I had to consider that tn is bounded and oscillatory, consider convergent subsequences, and show (sn+tn) had no unique limit, and therefore diverges. This part of the proof seemed less clear and I'm not sure if I can assert that because I have convergent subsequences of (tn) with multiple limits that (sn+tn) also has multiple limits.
I figure there has got to be some simple contradiction proof involving some triangle inequality trick that I'm just missing.
Thanks