Proving Infinitely Many Natural Numbers: Larson 4.1.6

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The discussion focuses on proving that there are infinitely many natural numbers a such that n^4 + a is not prime for any natural number n. Participants explore various forms of a, suggesting that a could be a multiple of 5 minus 1, which leads to an infinite set of solutions. The conversation also references Fermat's Little Theorem and Sophie Germain's identity as potential tools for the proof. Ultimately, the identity is highlighted as a useful approach to factor the expression. The thread concludes with appreciation for the insights shared, emphasizing the collaborative nature of problem-solving in mathematics.
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[SOLVED] Larson 4.1.6

Homework Statement


Prove that there are infinitely many natural numbers a with the following property: The number n^4+a is not prime for any number n.

Homework Equations


The Attempt at a Solution


I cannot even think of one such natural number a. :(
I need to find some way to factor this after we put some restrictions on a. That is we need to express a in a special form that makes this factorable. If a is equal to b^4, it is not necessarily factorable. In fact, I don't know of any power of b that will make it factorable. a cannot be a function of n. I really don't know what to do.
 
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a=4
a=(multiple of 5)-1
hence infinite
i guess
correct me if iam wrong
have you any idea of fermat theorm
n^5-n is divisible by 5
can be prooved ,it is a simpler form of fermat theorm
n(n^4-1) certainly n^4 -1 is divisible by 5
add any multiple of 5 to it
you get
 
Fermat's Little Theorem says that if p is a prime number that does not divide an integer n, then n^{p-1} \equiv 1 \mod p.

Therefore that will only apply when n is not divisible by 5. We need a proof for all n in N.
 
Maybe you can use Sophie Germain's identity:
a^4 + 4 b^4 = (a^2 + 2 b^2 + 2 a b) (a^2 + 2 b^2 - 2 a b).
 
durt said:
Maybe you can use Sophie Germain's identity:
a^4 + 4 b^4 = (a^2 + 2 b^2 + 2 a b) (a^2 + 2 b^2 - 2 a b).

Wow. Thanks. I'm glad I posted this question because I never would have thought of that.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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