Proving Invertible Elements in Algebraic Structure of Zn

  • Thread starter soulflyfgm
  • Start date
  • Tags
    Structure
In summary, the conversation discusses the algebraic structure of Zn and its properties, particularly in relation to multiplication and invertible elements. The problem at hand involves proving that the invertible elements in Zn are those that are relatively prime to n. To solve this, one can use Euclid's algorithm and the algebraic characterization of GCD, which states that if a and n are coprime, there exist integers x and y such that ax + ny = 1. This gives away the answer to the problem.
  • #1
soulflyfgm
28
0
For Zn = { 0, 1 ,...,n-1}, the algebraic structure (Zn, +, . ) is a "ring", i.e., it has nearly all of the usual properties of addition and multiplication that we use unconsciously most of the time(where the opertaions are defined by performing them in Z and then recording the remainder on division by n). In Z, of course, the only invertible elements with respect to multiplication (a for which there is some b such that ab = 1), are +-1. PRove that the invertible elements with respect to multiplication in Zn are exactly those elements a such that a and n are relatively priime; that is , gcd{a,n}=1

can some one give me a hint on wat to do in this problem? i woud really apriciate it!
 
Physics news on Phys.org
  • #2
What do you know about gcd? Are you familiar with Euclid's algorithm? If not, look it up on Wikipedia.
 
  • #3
yes

yes i know wat it is and i also know how to solve it.. but i don't see how am i suppost to use the euc alg to solve this problem.
any hint?
thank u
 
  • #4
Do you know the algebraic characterization of the GCD? IMHO, it is much more useful than the one involving divisibility.
 
  • #5
the euclidean algorithm states that if a and n are coprime there are integers x and y such that "SOMETHING THAT GIVES AWAY THE ANSWER"

if you do know the Euclidean algorithm then the answer is obvious, surely?
 

FAQ: Proving Invertible Elements in Algebraic Structure of Zn

What is an algebraic structure of Zn?

An algebraic structure of Zn is a mathematical system that consists of a set of elements and operations defined on those elements. In this structure, the elements are integers modulo n, where n is a positive integer.

What does it mean for an element to be invertible in an algebraic structure of Zn?

An element in an algebraic structure of Zn is said to be invertible if there exists another element in the structure that, when multiplied by the first element, results in the multiplicative identity element (1). In other words, the invertible element has a multiplicative inverse.

How do you prove that an element is invertible in an algebraic structure of Zn?

To prove that an element is invertible in an algebraic structure of Zn, you need to show that it has a multiplicative inverse. This can be done by finding another element in the structure that, when multiplied by the given element, results in the multiplicative identity element (1).

Why is it important to prove invertible elements in an algebraic structure of Zn?

Proving invertible elements in an algebraic structure of Zn is important because it ensures that the structure follows certain properties, such as the existence of a multiplicative inverse for every element. This makes the structure more predictable and easier to work with in mathematical equations.

Can an element be invertible in one algebraic structure of Zn but not in another?

Yes, an element can be invertible in one algebraic structure of Zn but not in another. This depends on the specific structure and the properties it follows. For example, an element may be invertible in a structure defined on integers modulo n, but not invertible in a different structure defined on rational numbers modulo n.

Back
Top