- #1
Dawson64
- 5
- 0
Why does it make sense ( when considering Z4)to form the factor group
Z4 / (2Z4) where kZn = {0, k mod n, 2k mod n, ..., nk mod n}?
I believe that this above factor group is isomorphic to Z2, but how can I prove this?
Z4 / (2Z4) where kZn = {0, k mod n, 2k mod n, ..., nk mod n}?
I believe that this above factor group is isomorphic to Z2, but how can I prove this?