Proving L3 is a Lorentz Transformation

In summary, the conversation is about showing that the product of two Lorentz transformations, L1 and L2, is also a Lorentz transformation, L3. This can be shown by demonstrating the invariance of the dot product under L3, or by writing L1 and L2 in terms of velocities and applying them consecutively. The definition of a Lorentz transformation is a transformation that does not change the space-time distance of a point to the origin, and mathematically is expressed as g_\alpha_\beta x^\alpha x^\beta = g_\mu_\nu \Lambda^\mu{}_\alpha \Lambda^\nu{}_\beta x^\alpha x^\beta. It can be shown that L
  • #1
martyf
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Homework Statement



L1 and L2 are two lorentz trasformation.
show that L3=L1 L2 is a lorentz trasformation too.


Homework Equations





The Attempt at a Solution

 
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  • #2
I could be wrong but I think it would be enough to show the invariance of the dot product under L3.
 
  • #3
what is the dot product?
 
  • #4
The scalar product, or inner product or whatever it's called of 4-vectors. In Minkowski space it's [tex]r_1 \cdot r_2 = c^2 t_1 t_2 - x_1 x_2 - y_1 y_2 - z_1 z_1[/tex] or with the signs reversed depending on the convention. But if you haven't yet done the Minkowski notation then you could write L1 and L2 as Lorentz transformations with some velocities and show by applying them consecutively that L3 has the same form.
 
  • #5
I write better :

I have: [tex]\Lambda [/tex] [tex]^{\mu}_{\nu}[/tex] and [tex]\Lambda\widetilde{} [/tex] [tex]^{\mu}_{\nu}[/tex] : lorentz trasformations.

Show that [tex]\Lambda\overline{}[/tex] [tex]^{\sigma}_{\rho}[/tex] = [tex]\Lambda\widetilde{} [/tex] [tex]^{\sigma}_{\mu}[/tex] [tex]\Lambda [/tex] [tex]^{\mu}_{\rho}[/tex] is a lorentz trasformation
 
  • #6
What is the definition of Lorentz transformation given in your notes and/or text?
 
  • #7
a trasfonmation that not change the space-time distance of a point to the origin.
 
  • #8
martyf said:
a trasfonmation that not change the space-time distance of a point to the origin.

Can you write a definition in terms of mathematics, i.e., [tex]\Lambda^\mu{}_\nu[/itex] is a Lorentz transformation iff ... ?
 
  • #9
...if :

x[tex]^{2}_{0}[/tex] - r [tex]^{2}[/tex]= ([tex]\Lambda[/tex] [tex]^{0}_{\nu}[/tex] x[tex]_{0}[/tex])[tex]^{2}[/tex] -( [tex]\Lambda[/tex] [tex]^{\mu}_{\nu}[/tex] r[tex]_{\mu}[/tex])[tex]^{2}[/tex]
 
  • #10
is it right?
 
  • #11
You don't have the indices right, your right hand side depends on on [tex]\nu[/tex] whereas the left hand side doesn't. It should be:

[tex](x^0)^2 - r^2 = (\Lambda^0{}_\nu x^\nu)^2 - (\Lambda^j{}_\nu x^\nu)^2[/tex]

Where j goes from 1 to 3. More compactly:

[tex]g_\alpha_\beta x^\alpha x^\beta = g_\mu_\nu \Lambda^\mu{}_\alpha \Lambda^\nu{}_\beta x^\alpha x^\beta[/tex]

Where g is the metric. Use the fact that L1 and L2 satisfy this to show that L3 satisfies it as well.
 
  • #12
L1 and L2 are two generical lorents tranformation. I must demostrate that their product is also a lorentz transormation.
Can I demostrate :

[tex]g_\alpha_\beta x^\alpha x^\beta = g_\mu_\nu \Lambda^\mu{}_\alpha \Lambda^\nu{}_\beta x^\alpha x^\beta[/tex]

with \Lambda =L3= L1 L2 ?
 
  • #13
Yes you can.
 

FAQ: Proving L3 is a Lorentz Transformation

What is L3 in the context of Lorentz transformations?

L3 is one of the three fundamental Lorentz transformations, along with L1 and L2. It describes the transformation of coordinates between two inertial frames of reference moving at a constant velocity relative to each other.

How is L3 derived?

L3 can be derived mathematically by applying the principles of special relativity and the Lorentz transformation equations. It involves manipulating the equations and solving for the transformation matrix elements.

What is the significance of proving L3 as a Lorentz transformation?

Proving L3 as a Lorentz transformation is important because it confirms the validity of the Lorentz transformation equations and the principles of special relativity. It also provides a mathematical framework for understanding the effects of time dilation and length contraction.

Can L3 be used for practical applications?

Yes, L3 can be used in practical applications such as in the field of particle physics and in the development of technologies like GPS. It helps to accurately calculate and adjust for the effects of time dilation and length contraction in these systems.

Are there any limitations to L3 as a Lorentz transformation?

Like all mathematical models, L3 has limitations and is not a perfect representation of reality. It only applies to inertial frames of reference and does not account for acceleration or gravity. Additionally, it does not take into account quantum effects at the subatomic level.

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