- #1
Josh1079
- 47
- 0
Hi,
I'm kind of stuck with this theorem stating that: if A is an unipotent matrix, then exp(log A) = A and also if X is nilpotent then log(exp X) = X
Does anyone know any good approaches to prove this?
I know that for unipotent A, logA will be nilpotent and that for nilpotent X, exp(X) will be unipotent
Thanks!
I'm kind of stuck with this theorem stating that: if A is an unipotent matrix, then exp(log A) = A and also if X is nilpotent then log(exp X) = X
Does anyone know any good approaches to prove this?
I know that for unipotent A, logA will be nilpotent and that for nilpotent X, exp(X) will be unipotent
Thanks!