- #1
doggie_Walkes
- 20
- 0
This has stuck with me for a long time, i just can't do it.
If the sequence of functions, fn(x): R+ --> R
where fn(x) is defined as
fn(x) = x/n if 0 is greater than and equal to x, x is less than and equal to n
fn(x) = 1 if x is strickly greater than n
I need to show that the fn(x) is pointwise convergence so the zero function. f(x) =0
If the sequence of functions, fn(x): R+ --> R
where fn(x) is defined as
fn(x) = x/n if 0 is greater than and equal to x, x is less than and equal to n
fn(x) = 1 if x is strickly greater than n
I need to show that the fn(x) is pointwise convergence so the zero function. f(x) =0