Proving Set Theory Problem: Counterexample for (A-B)intersect(A-C)=empty set

In summary, the conversation involved asking for help with a set theory problem and providing a counterexample to prove a statement false. The counterexample involved sets A={4,26}, B={4,23}, and C={26,23} and showed that if (A-B)intersect(A-C) equals the empty set, then B intersect C must also equal the empty set, which is a false statement.
  • #1
physicsgirlie26
43
0
I was wondering if someone could please look over my proof of this set theory problem and let me know if I am doing it right or not and give me some help.


Provide a counterexample for the following:

If (A-B)intersect(A-C)=empty set, then B intersect C = empty set.

Proof:

Assume that (A-B)intersect(A-C) does not equal the empty set. Let A={4,26}, B={4,23}, and C={26,23}. Since (A-C)=26 and (A-C)=4, that means that (A-B)intersect(A-C) does not equal the empty set. So B intersect C equals 23 which is also not the empty set.


Thank you for your help! :smile:
 
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  • #2
physicsgirlie26 said:
I was wondering if someone could please look over my proof of this set theory problem and let me know if I am doing it right or not and give me some help.


Provide a counterexample for the following:

If (A-B)intersect(A-C)=empty set, then B intersect C = empty set.

Proof:

Assume that (A-B)intersect(A-C) does not equal the empty set. Let A={4,26}, B={4,23}, and C={26,23}. Since (A-C)=26 and (A-C)=4, that means that (A-B)intersect(A-C) does not equal the empty set. So B intersect C equals 23 which is also not the empty set.


Thank you for your help! :smile:

that doesn't quite work, to show

If (A-B)intersect(A-C)=empty set, then B intersect C = empty set is a false statement, you need to find A, B, C such that (A-B)intersect(A-C)=empty set but B intersect C != empty set
 
  • #3
Ok how about this:

Proof:

Let A={4,26}, B={4,23}, and C={26,23}. If (A-C)=26 and (A-C)=4, that means that (A-B)intersect(A-C) equals the empty set. But B intersect C = 23 which is not the empty set, therefore there is a contradiction.

How is that?
 
  • #4
physicsgirlie26 said:
Ok how about this:

Proof:

Let A={4,26}, B={4,23}, and C={26,23}. If (A-C)=26 and (A-C)=4, that means that (A-B)intersect(A-C) equals the empty set. But B intersect C = 23 which is not the empty set, therefore there is a contradiction.

How is that?

good work :)

(I think you mean A-B = {26} though)
 
  • #5
haha got it!


Thank you!
 

FAQ: Proving Set Theory Problem: Counterexample for (A-B)intersect(A-C)=empty set

What is set theory?

Set theory is a branch of mathematics that deals with the study of sets, which are collections of objects or elements. It is used to understand the relationships between different sets and their elements.

What does (A-B)intersect(A-C)=empty set mean?

This notation means the intersection of the sets A-B and A-C is an empty set, or in other words, there are no elements that are common to both sets A-B and A-C.

What is a counterexample?

A counterexample is a specific instance that disproves a statement or theory. In the context of set theory, it is a set of elements that shows the given statement to be false.

Why is it important to find a counterexample for (A-B)intersect(A-C)=empty set?

Finding a counterexample for this statement can help us understand the limitations of set theory and the conditions under which certain statements are true or false. It also allows us to refine our understanding of set operations and their properties.

What is the process for finding a counterexample for (A-B)intersect(A-C)=empty set?

The process involves identifying two sets A and B, and then finding a third set C that contains elements that are both in A and B, as well as elements that are not in either A or B. This will result in a counterexample for the given statement.

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