Proving Suprenum of A and B: Bob's Question

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In summary, two non-empty sets A and B, bounded above by R, need to be proven that sup(A \cup B) = max(sup A, sup B). This means that sup(A \cup B) is the largest of the two numbers sup A and sup B. This can be written as sup(A) < sup(A \cup B) and sup(B) < sup(A \cup B). To prove this, it can be shown that sup(A) < sup(A \cup B) is true. The definition of Supremum is that every non-empty, bounded above subset of R has a smallest upper bound. So, sup(A \cup B) has a larger smallest upper bound than sup(A) and sup
  • #1
Bob19
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Hello

I have two non-empty sets A and B which is bounded above by R.

Then I'm tasked with proving that

[tex]sup(A \cup B) = max(sup A, sup B) [/tex]

which supposedly means that [tex]sup(A \cup B) [/tex] is the largest of the two numbers sup A and sup B.

Can this then be written as [tex]sup(A) < sup(A \cup B) [/tex] and [tex]sup(B) < sup(A \cup B)[/tex] ?

Can this then be proven by showing that [tex]sup(A) < sup(A \cup B) [/tex] is true?

Or am I totally on the wrong path here??

/Bob
 
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  • #2
correct your tex and just verify the definitions of sup.
 
  • #3
matt grime said:
correct your tex and just verify the definitions of sup.
My definition of Supremum is a follows:
every non-empty, bounded above subset of R has a smallest upper bound.

Then [tex]sup(A \cup B)[/tex] has a larger smallest upper bound than sup(A) and sup(B) according to the definition of Supremum ?
Does this prove the given argument in my first post?
/Bob

p.s. If my idear is true, can this then be proven by taking a number z, which I then prove [tex]z \in sup(A \cup B)[/tex] but [tex]z \notin sup(A) [/tex] and [tex]z \notin sup(B)[/tex] ?

/Bob
 
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  • #4
why are you treating sup as a set (and taking elements in it?). Sup is not a set, it is an element of R.

Sup of a set is the least upper bound (when it exists)

obivously the least upper bound of AuB is the max of the least upper bounds, but you need to verify it, ie show it is an upper bound, and show it is the least upper bound. The first is easy, the second slightly harder.
 
  • #5
matt grime said:
obivously the least upper bound of AuB is the max of the least upper bounds, but you need to verify it, ie show it is an upper bound, and show it is the least upper bound. The first is easy, the second slightly harder.


Okay those two aspects then prove the argument that

sup(AuB) = max(sup A, sup B) ?


/Bob
 
  • #6
As I explained to someone else earlier tonight, I can easily see the answer becuase of experience, YOU need to demonstrate that you understand the answer by not having to let me fill in any blanks. If you don't see that an argument proves something then YOU need to do some work to rectify that, not me.
 

FAQ: Proving Suprenum of A and B: Bob's Question

What is the definition of supremum?

The supremum of a set is the smallest upper bound that is greater than or equal to all the elements in the set.

How do you prove the supremum of a set?

To prove the supremum of a set, you must show that the proposed upper bound is greater than or equal to all the elements in the set, and that there is no smaller upper bound that satisfies this condition.

What is the significance of proving the supremum of a set?

Proving the supremum of a set is important because it allows us to determine the maximum value of a set, which is useful in many mathematical and scientific applications.

What is the difference between supremum and maximum?

The supremum of a set is the smallest upper bound that is greater than or equal to all the elements in the set, while the maximum is the largest element in the set. The supremum may or may not be an actual element in the set, while the maximum must be an element in the set.

Can a set have multiple supremums?

No, a set can only have one supremum. If a set has multiple upper bounds, the supremum will be the smallest of these upper bounds.

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