Proving that solutions of a equation are irrational

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In summary, to prove that the solutions of the equation x^3 + x + 1 = 0 are irrational, we can use the Rational Root Theorem and prove by contradiction. This is similar to the proof of the irrationality of √2. Assuming that x is rational and using the equation, we can show that it leads to a contradiction, proving that there are no rational roots.
  • #1
ranga519
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how to prove that solutions of the following equation are irrational

x^3 + x + 1 = 0
 
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  • #2
ranga519 said:
how to prove that solutions of the following equation are irrational

x^3 + x + 1 = 0

Hi Ranga,

I do not know what your course material says, but we have the Rational Root Theorem to work with.
Since neither $x=-1$ nor $x=1$ is a solution, that implies that there is no rational root.
 
  • #3
You can prove it by contradiction. It is essentially the same proof as the proof of $\sqrt 2$ being irrational.

Assume x is rational, then x can be given as $x=p/q$ where p and q have no common primefactors. The equation becomes $$\frac{p^3}{q^3}+\frac{p}{q}+1=0 \Leftrightarrow p^3=-q^2(p+q)$$
Can you se the contradiction now?
 

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