- #1
murmillo
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Homework Statement
Let G be a cyclic group of order n, and let r be an integer dividing n. Prove that G contains exactly one subgroup of order r.
Homework Equations
cyclic group, subgroup
The Attempt at a Solution
Say the group G is {x^0, x^1, ..., x^(n-1)}
If there is a subgroup H of order r, it must be cyclic, because: why? I can't figure it out, but I have a feeling that it must be cyclic.
H is generated by some element, call it b=x^m. Since x^r = 0, we have (x^m)(x^m)... (r times) = 0. Thus mr=n and H must be the cyclic group generated by x^(n/r).
I have a feeling that I have the right idea but I don't know how to show that a group is cyclic. Could someone help?