Proving the Half-Angle Formula for Tangent Using Trigonometric Identities

  • Thread starter xonicole
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In summary, the conversation is about finding a solution for the equation tanx/2 = (1-cosx)/sinx. The suggested methods for solving this equation are using Weierstrass substitution or Double angle identities. The first method involves substituting the values of x/2 into the Double angle identities and simplifying the equation. The second method was not explained further due to lack of information provided by the person seeking help.
  • #1
xonicole
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Homework Statement


tanx/2 = (1-cosx)/sinx


Homework Equations





The Attempt at a Solution


This is where i got on the right side
i don't know where to finish...(1-cosx)/sinx
 
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  • #2
Well, are you familiar with Weierstrass substitution? They are also known as t-formula:
http://pear.math.pitt.edu/Calculus2/week3/3_2li5.html

Another method would be to use the Double angle identities:
[tex]\cos (2\theta) = 1- 2\sin^2 \theta[/tex] and [tex]\sin (2\theta) = 2 \sin \theta \cos \theta[/tex].

Into those, let [itex]\theta = x/2[/itex], and put those back into what you have and simplify.
 
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  • #3
I found that a lot of people have been telling me that but i don't understand how you use that to make the sides equal is there a way you can show me step by step
 
  • #4
No really I can't ! You didn't even tell me which of the two methods I posted you want help with. Show us what you have tried to do yourself, so we can help you get over what you're stuck with.
 

FAQ: Proving the Half-Angle Formula for Tangent Using Trigonometric Identities

What is the equation for proving tanx/2 = cscx - cotx?

The equation is: tanx/2 = cscx - cotx.

How do you prove the equation tanx/2 = cscx - cotx?

To prove this equation, you can use the half-angle formula for tangent: tanx/2 = ±√((1-cosx)/1+cosx), and the reciprocal identities for cosecant and cotangent: cscx = 1/sinx and cotx = cosx/sinx.

What is the significance of proving tanx/2 = cscx - cotx?

This equation is significant because it shows the relationship between the half-angle of a tangent function and the cosecant and cotangent functions. It also has various applications in calculus and trigonometry.

Can you provide an example of proving tanx/2 = cscx - cotx?

Sure, for example, let x = π/4. Using the values of sin(π/4) = cos(π/4) = √2/2, we can plug into the equation tan(π/8) = ±√((1-√2/2)/1+√2/2). Simplifying, we get tan(π/8) = ±1/√2 = ±√2/2. Then using the values of csc(π/4) = √2 and cot(π/4) = 1, we get csc(π/8) - cot(π/8) = √2 - 1/√2 = (√2+1)/2. Therefore, tan(π/8) = (√2+1)/2 = csc(π/8) - cot(π/8).

How can this equation be used in real-world situations?

This equation can be used in various real-world situations, such as engineering, physics, and navigation. For example, it can be used to calculate the height of an object based on its distance and angle of elevation, or to find the velocity of an object moving in a circular path.

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