- #1
physicsgal
- 164
- 0
im suppose to do some calculations to prove whether or not the pendulum demonstrates the law of conservation of energy.
mass of pendulum = 240.3g = 0.2403 kg
diamter of pendulum bob = 3.50
initial height of pendulum bob = 48 cm = 0.48 m
length of pendulum string = 2.14 m
time interval of photogate light interruption = 11.8 m/s
so there's position 'A' and position 'B'
for 'A"
Emechanical = Ek + Eg
= (0.5)mv^2 + mgh
= 0 + (0.2403kg)(9.8)(0.48m)
= 1.13J
for 'B'
Emechanical = Ek + Eg
= (0.5)mv^2 + mgh
= (.5)(0.2403kg)(11.8^2) + 0
= 16.73J
i must be missing something (my calculations aint proving anything).. any help will be appreciated!
~Amy
mass of pendulum = 240.3g = 0.2403 kg
diamter of pendulum bob = 3.50
initial height of pendulum bob = 48 cm = 0.48 m
length of pendulum string = 2.14 m
time interval of photogate light interruption = 11.8 m/s
so there's position 'A' and position 'B'
for 'A"
Emechanical = Ek + Eg
= (0.5)mv^2 + mgh
= 0 + (0.2403kg)(9.8)(0.48m)
= 1.13J
for 'B'
Emechanical = Ek + Eg
= (0.5)mv^2 + mgh
= (.5)(0.2403kg)(11.8^2) + 0
= 16.73J
i must be missing something (my calculations aint proving anything).. any help will be appreciated!
~Amy