Proving the Subspace Property of U + W

In summary, we need to show that the set U + W, defined as the set of all vectors in V that can be written as the sum of vectors in U and W, is a subspace of V. To do so, we must demonstrate that it is closed under vector addition and scalar multiplication. To show closure under addition, we can use the fact that if x and y are in U + W, then x + y must also be in U + W. This is because x + y can be expressed as the sum of vectors in U and W, making it an element of U + W. Therefore, U + W is closed under addition.
  • #1
Warpenguin
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Homework Statement


Let U and W be subspaces of a vector space V
Show that the set U + W = {v ∈ V : v = u + w, where u ∈ U and w ∈ W} is a subspace of V

Homework Equations




The Attempt at a Solution


I understand from this that u and w are both vectors in a vector space V and that u+w is a vector in a vector space V but I'm not sure how to apply the rules to this problem in order to show that U + W is a subspace of V
 
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  • #2
Remember that the definition of "subspace" is a subset that is closed under vector addition and scalar multiplication. If x is in U+ W, then there exist vectors u in U and v in V such that x= u+ v. Similarly, if y is in U+ W, then there exist vectors u' in U and v' in V such that y= u'+ v'. Can you say the same thing about x+ y? x+ y is equal to the sum of what vectors in U and W? What about ax where a is a scalar?
 
  • #3
Well if x and y are vectors in U + W then x+y will be a vector in U + W. x + y = u + w + u' + w' = (u + u') + (w + w')? u + u' is in U and w + w' is in W. Therefore x + y is in U + W. So U + W is closed under addition. Is this right?
 
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FAQ: Proving the Subspace Property of U + W

What is a subspace in algebra?

A subspace in algebra is a subset of a vector space that satisfies three properties: closure under addition, closure under scalar multiplication, and contains the zero vector. In other words, a subspace is a smaller space within a larger space that still follows the rules of vector addition and scalar multiplication.

How do you prove that a set is a subspace?

To prove that a set is a subspace, you must show that it satisfies the three properties mentioned above: closure under addition, closure under scalar multiplication, and contains the zero vector. This can be done by showing that any two vectors in the set can be added together to get another vector in the set, and that any vector in the set can be multiplied by a scalar to get another vector in the set.

What is the difference between a subspace and a vector space?

A subspace is a subset of a vector space, while a vector space is the entire set of vectors. A subspace must still follow the rules of vector addition and scalar multiplication, while a vector space may have additional properties or operations.

Can a subspace have more than one dimension?

Yes, a subspace can have any number of dimensions as long as it satisfies the three properties of closure under addition, closure under scalar multiplication, and contains the zero vector.

Why is proving a subspace important in algebra?

Proving a subspace is important in algebra because it allows us to identify and work with smaller spaces within larger vector spaces. This can simplify calculations and make problem-solving more efficient. Additionally, understanding subspaces is crucial for more advanced topics in linear algebra and other areas of mathematics.

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