- #1
bedi
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Z is the set of integers. Prove that (3/7)Z + (11/2)Z = (1/14)Z
Attempt:
By definition,
(3/7)Z+(11/2)Z={3k/7 + 11m/2 : k,m € Z} = {(6k + 77m)/14 : k,m € Z}.
Showing that 3/7Z+11/2Z is a subset of 1/14 Z is easy but I can't prove the converse. Can't show that whatever n€1/14Z I take satisfies that n€3/7Z+11/2Z.
Attempt:
By definition,
(3/7)Z+(11/2)Z={3k/7 + 11m/2 : k,m € Z} = {(6k + 77m)/14 : k,m € Z}.
Showing that 3/7Z+11/2Z is a subset of 1/14 Z is easy but I can't prove the converse. Can't show that whatever n€1/14Z I take satisfies that n€3/7Z+11/2Z.