Pulling a Box of Sand: Tension and Friction

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To determine the optimal angle for pulling a box of sand without exceeding a tension of 792 N, the focus is on maximizing the function m(θ) = C(sinθ + cosθ), where C represents the coefficient of static friction. The discussion highlights the need to derive the angle by setting the derivative of m(θ) with respect to θ to zero. Participants express frustration over the lack of similar examples in the textbook, making it difficult to approach the problem. The weight of the sand and box can be calculated once the optimal angle is determined. Understanding the relationship between tension, friction, and angle is crucial for solving the problem effectively.
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Homework Statement



An initially stationary box of sand is to be pulled across a floor by means of a cable in which the tension should not exceed 792 N. The coefficient of static friction between the box and the floor is 0.37. (a) What should be the angle between the cable and the horizontal in order to pull the greatest possible amount of sand, and (b) what is the weight of the sand and box in that situation?

Homework Equations



Maybe F=ma? I have no idea where to begin on this. So little information is given it makes me think there's some mistake.

The Attempt at a Solution



I drew a box with a string attached to it and that's all I could figure out. The book gives no examples that are even within a light year of being similar to this, so that thing is worthless.
 
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You want to maximize m(θ) = C(sinθ + cosθ)

see,
 

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Spinnor said:
You want to maximize m(θ) = C(sinθ + cosθ)

see,

Thanks for the response.

I still don't quite see how I can figure out the problem. I don't have enough numerical values to plug in, from what I can tell.
 
Plot sinθ + cosθ

You want to maximize m(θ) = C(sinθ + cosθ)

Set d m(θ)/dθ = 0
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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