- #1
Taylor_1989
- 402
- 14
Homework Statement
Q:[/B]An ultrasound department seeks your advice regarding scans they perform to visualise and confirm foetal heart beating. They wish to know what imaging frame rate should be set in order to visualise the heart movement reliably but achieve the maximum possible reduction in ultrasound exposure of the foetus. They explain that the typical scan conditions are a foetal heartrate of 150 beats per minute, imaged using a maximum scan display depth of 10 cm.
You research the scanner and discover that:
(a) the line density for imaging is fixed at 100 lines per frame
(b) the pulse repetition frequency is affected by a minimum delay of 200 microseconds at the end of each pulse-echo cycle for the scanner to process the returning signals before the next pulse-echo cycle is commenced and
(c) the scanner is designed to run initially at the maximum frame rate achievable for the depth of scan that is set, but that the frame rate may then be adjusted down by the operator.
Note: The frame rate is expressed in frames per second or fps.
Which of the following is the best advice to give? Please select one answer only
a.
Adjust the frame rate down to 10 fps and achieve an exposure reduction of approximately 87 %
b.
Adjust the frame rate down to 5 fps and achieve an exposure reduction of approximately 94 %
c.
Adjust the frame rate down to 5 fps and achieve an exposure reduction of approximately 83 %
d.
Adjust the frame rate down to 10 fps and achieve an exposure reduction of approximately 67 %
e.
Adjust the frame rate down to 2.5 fps and achieve an exposure reduction of approximately 97 %
f.
Adjust the frame rate down to 2.5 fps and achieve an exposure reduction of approximately 92 %
Homework Equations
[/B]
Image depth
$$PRF=1540/(2*D_{max}) [1]$$
PRF = frame rate x line density [2]
The Attempt at a Solution
Here what I know the inverse of the PRF will give the me pulse echo period, which is the time between each pulse, so as I understand the transducer send out a plus and then switched off until the next plus which is the PEP (pulse echo period), now this has to be greater than the return time of the pulse which in this case it is ##1/7700=129.8701299\mu s## value was obtained from using the [1] so as the time it would take the sound wave to travel is ##t=0.2/1540=130\mu s## so it only by a fraction which is why I think the ##200\mu s## is included. so given this I did the following:
I then converted this into the pulse echo which is 1/7700Hz
after this I add the 200 microsecond to it as this is the delay in the transducer I believe between pluses so I did the following: 1/7700Hz +1/5000hz=127/385000 taking the inverse gave me
3031.496063hz
I then took 3031.496063hz and dived it by 100 as that the line density so I could get a frame rate which was 30.31496063fps
I then took the percentage decrease of each one with this value i.e
((30.31496063-10)/30.31496063)*100=67.0129870%
((30.31496063-5)/30.31496063)*100=83.50649351%
((30.31496063-2.5)/30.31496063)*100=91.7532675%
which give me 3 percentages that are in the ans s my issue is it say in the ans that it approximate which leaves me in a problem with either rounding 91.7 to 92 or choose the 67.012 as this seems to be the most correct with the ans to pick as there is no rounding involved. Can anyone see a problem with the way I have approached this problem?
sorry for the mix of latex my I have been having issue with my keyboard layout, so I just had to finish the rest of like so.