Push Me Pull You centre of mass motion

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The discussion revolves around a physics problem involving two identical blocks connected by a spring on a frictionless surface. The blocks are compressed against a wall and then released, prompting an analysis of the center of mass motion during two phases: when one block is in contact with the wall and when it is not. Participants suggest starting by treating the block against the wall as fixed to simplify calculations. The importance of determining the normal reaction force from the wall is emphasized, as it indicates when contact is lost. Understanding these phases is crucial for solving the problem effectively.
Maybe_Memorie
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Homework Statement



Two identical blocks of mass m are attached via a massless spring of
spring constant k. The length of the spring in equilibrium is l. The
system moves on a frictionless horizontal plane.

With one block resting against a wall, the two blocks are pushed to-
gether, so that the spring gets compressed until its length is l/2, and
then released.
Find the motion of the centre of mass of the system after it is released.
Note: You should distinguish the two phases in which the block to the
left (i) is in contact with the wall and (ii) has lost contact with the
wall.

Homework Equations



F = ma
F= -kx

The Attempt at a Solution



I just need a hint on how to get startedwith this one please.
 
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Hi Maybe_Memorie! :smile:

I assume you can do the part where there's still contact with the wall (ie, by pretending that the block is fixed to the wall :wink:)?

ok, find the normal reaction from the wall …

when that's zero, contact will be lost, and from then on you can assume that the wall isn't there! :biggrin:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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