- #1
Hope Lansing
- 7
- 0
I just want to know if I am understanding this correctly.
I am wondering what effect the rolling resistance has on the motion of a car when pushed, or when rolling to a stop. The mass of the car is 1,000kg.
I looked up on a table to find the rolling resistance coefficient of a normal car tire on asphalt and got .03 so that is the value I am using.
Frr = .03 * 1,000kg * 9.8m/s² = 294 N
a = 294 N / 1,000 kg = .294m/s²
Question 1 :
Does this mean that if a 1,000kg car is at rest in nuetral, and I want to get that car rolling, I would need to apply a force greater than 294 N before the car would even begin to roll?
Question 2 :
If this car was already in motion at say, 3m/s, would it come to a stop in about 10.2 seconds? (t = 3m/s / .294m/s² = 10.2s)
I am ignoring any other sources of friction(ball bearings, etc), and the asphalt is perfectly level.
Any help would be greatly appreciated. Thank you.
I am wondering what effect the rolling resistance has on the motion of a car when pushed, or when rolling to a stop. The mass of the car is 1,000kg.
I looked up on a table to find the rolling resistance coefficient of a normal car tire on asphalt and got .03 so that is the value I am using.
Frr = .03 * 1,000kg * 9.8m/s² = 294 N
a = 294 N / 1,000 kg = .294m/s²
Question 1 :
Does this mean that if a 1,000kg car is at rest in nuetral, and I want to get that car rolling, I would need to apply a force greater than 294 N before the car would even begin to roll?
Question 2 :
If this car was already in motion at say, 3m/s, would it come to a stop in about 10.2 seconds? (t = 3m/s / .294m/s² = 10.2s)
I am ignoring any other sources of friction(ball bearings, etc), and the asphalt is perfectly level.
Any help would be greatly appreciated. Thank you.