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cathaloc2
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I have the question and the answer but just keep getting a different answer so here it goes.
Darcy law h=(4fLv2(square root sign))/2gD
h=head of water(m)
f=Friction coefficient (0.007)
L= equivalent length of pipework (m)
v= velocity (m/s)
g= acceleration due to gravity (9.81m/s2)
D= pipe diameter
Q. Over a distance of 25m, a 25mm diameter pipe loses 7m of pressure. Using the D'Arcy Equation, determine the velocity of water in the pipe and the flowrate in litres per second.
Answer = v= 0.215m/s q= 1.086l/s
Any help would be great thanks
My attempt
7=4x.007x25xv2/2x9.81x.025
v2=5x2x9.81x.025/4x.007x25
v2= 2.4525/.7
v2=3.5035
v=1.87m/s
Darcy law h=(4fLv2(square root sign))/2gD
h=head of water(m)
f=Friction coefficient (0.007)
L= equivalent length of pipework (m)
v= velocity (m/s)
g= acceleration due to gravity (9.81m/s2)
D= pipe diameter
Q. Over a distance of 25m, a 25mm diameter pipe loses 7m of pressure. Using the D'Arcy Equation, determine the velocity of water in the pipe and the flowrate in litres per second.
Answer = v= 0.215m/s q= 1.086l/s
Any help would be great thanks
My attempt
7=4x.007x25xv2/2x9.81x.025
v2=5x2x9.81x.025/4x.007x25
v2= 2.4525/.7
v2=3.5035
v=1.87m/s