- #1
mtal
- 6
- 0
Hello,
Let [itex]X[/itex] be a set of [itex]N[/itex] lognormal prices (in dollars), meaning
[tex]\log(X) = Y \sim MN(\mu_Y , \Sigma_Y) ,[/tex]
i.e. the log of [itex]X[/itex] follows a multivariate normal distribution.
Imagine now that one wants to compute various quantiles for this set, e.g. 2.5%, 50% and 97.5\%, and does this by simulating 100k draws from the distribution above.
You then get say a [itex]100k \times N[/itex] matrix, and to get the total value you'd find these three quantiles for each of the [itex]N[/itex] prices, resulting in a [itex]N \times 3[/itex] matrix of quantiles, and then simply add up each of the three columns giving three numbers which represent the total quantiles for the whole set.
So, my question is:
How would one go about transforming the information for the quantiles for the whole set from log-dollars to dollars?
I am of course aware of the exponential function, so what I'm asking is how and where in this process do I use it?
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My main idea is this:
The three final quantiles, 2.5%, 50% and 97.5\%, represent the log-quantiles of the set as a whole, say [itex] V_{2.5\%}, V_{50\%}[/itex] and [itex] V_{97.5\%}[/itex]. They also have their log/exp-counterparts, e.g. [itex] V_{50\%} = log(X_{50\%})[/itex].
Now, the difference between, for example, the 50% and 2.5%, [itex]V_{50\%} - V_{2.5\%}[/itex] could then be represented as
[tex] log(X_{50\%}) - log(X_{2.5\%}) = log\left(\frac{X_{50\%}}{X_{2.5\%}}\right),[/tex]
meaning that the log difference can be interpreted as log-proportional difference. Thus one could just exp and inverse this value and get
[tex] exp \left( log \left( \frac{ X_{50\%} }{ X_{2.5\%} } \right) \right)^{-1} = \frac{X_{2.5\%}}{X_{50\%}} [/tex]
which gives you the proportional difference of the quantiles in dollars, instead of log-dollars. With this information the 2.5% quantile can be obtained by multiplying [itex] X_{2.5\%}[/itex] with the mean of the [itex]N[/itex] prices.
Or am I way off here?
Any help is greatly appreaciated.
Let [itex]X[/itex] be a set of [itex]N[/itex] lognormal prices (in dollars), meaning
[tex]\log(X) = Y \sim MN(\mu_Y , \Sigma_Y) ,[/tex]
i.e. the log of [itex]X[/itex] follows a multivariate normal distribution.
Imagine now that one wants to compute various quantiles for this set, e.g. 2.5%, 50% and 97.5\%, and does this by simulating 100k draws from the distribution above.
You then get say a [itex]100k \times N[/itex] matrix, and to get the total value you'd find these three quantiles for each of the [itex]N[/itex] prices, resulting in a [itex]N \times 3[/itex] matrix of quantiles, and then simply add up each of the three columns giving three numbers which represent the total quantiles for the whole set.
So, my question is:
How would one go about transforming the information for the quantiles for the whole set from log-dollars to dollars?
I am of course aware of the exponential function, so what I'm asking is how and where in this process do I use it?
------------------------------------------------------------------------------------------------------------------------------------------------------
My main idea is this:
The three final quantiles, 2.5%, 50% and 97.5\%, represent the log-quantiles of the set as a whole, say [itex] V_{2.5\%}, V_{50\%}[/itex] and [itex] V_{97.5\%}[/itex]. They also have their log/exp-counterparts, e.g. [itex] V_{50\%} = log(X_{50\%})[/itex].
Now, the difference between, for example, the 50% and 2.5%, [itex]V_{50\%} - V_{2.5\%}[/itex] could then be represented as
[tex] log(X_{50\%}) - log(X_{2.5\%}) = log\left(\frac{X_{50\%}}{X_{2.5\%}}\right),[/tex]
meaning that the log difference can be interpreted as log-proportional difference. Thus one could just exp and inverse this value and get
[tex] exp \left( log \left( \frac{ X_{50\%} }{ X_{2.5\%} } \right) \right)^{-1} = \frac{X_{2.5\%}}{X_{50\%}} [/tex]
which gives you the proportional difference of the quantiles in dollars, instead of log-dollars. With this information the 2.5% quantile can be obtained by multiplying [itex] X_{2.5\%}[/itex] with the mean of the [itex]N[/itex] prices.
Or am I way off here?
Any help is greatly appreaciated.