- #1
thatboi
- 133
- 18
Hi all,
When working in the Heisenberg picture, we can represent implementing time evolution on an operator via a Hamiltonian H through a quantum circuit type picture like the following:
where time is on the vertical axis and increases going up and the block represents the unitary gate ##e^{-iHt}##. However, I am struggling to picture how this would look on a circuit if instead, we wanted to conjugate some operator ##O## via the unitaries ##e^{-iH_{1}t},e^{-iH_{2}t}## where ##[H_{1},H_{2}] \neq 0##. That is, ##O(t) = e^{-iH_{2}t}e^{-iH_{1}t}Oe^{iH_{1}t}e^{iH_{2}t}##. Vertically stacking the gates on top of each other doesn't seem to make much sense to me since it would then seem to imply that we have elapsed a time ##2t## through this time evolution.
Any thoughts?
When working in the Heisenberg picture, we can represent implementing time evolution on an operator via a Hamiltonian H through a quantum circuit type picture like the following:
where time is on the vertical axis and increases going up and the block represents the unitary gate ##e^{-iHt}##. However, I am struggling to picture how this would look on a circuit if instead, we wanted to conjugate some operator ##O## via the unitaries ##e^{-iH_{1}t},e^{-iH_{2}t}## where ##[H_{1},H_{2}] \neq 0##. That is, ##O(t) = e^{-iH_{2}t}e^{-iH_{1}t}Oe^{iH_{1}t}e^{iH_{2}t}##. Vertically stacking the gates on top of each other doesn't seem to make much sense to me since it would then seem to imply that we have elapsed a time ##2t## through this time evolution.
Any thoughts?