- #1
novop
- 124
- 0
Homework Statement
If x is the position of a particle then the expectation value of x, <x> is :
(I got lazy and just copied an image from Wiki, just pretend <x> is on the lhs of the eqn)
When Griffith derives an expression for d<x> / dt, he uses the fact that dx/dt is zero, since "the wave function collapses after the first measurement and subsequent measurements will repeat the same result, if they're performed quickly."
What does he mean by this? Surely the wave function evolves according to the schrodinger equation after the first measurement... so how fast must the subsequent measurements be taken to ensure that dx/dt = 0?