Quantum Mechanics I, finding impuls wavefunction.

In summary, "Quantum Mechanics I" discusses the concept of the impulse wavefunction, which is a mathematical representation of a particle's state in quantum mechanics. It focuses on the properties of wavefunctions, the relationship between position and momentum, and how to derive the impulse wavefunction from fundamental principles. The text emphasizes the significance of the wavefunction in predicting the behavior of quantum systems and its role in understanding phenomena such as uncertainty and superposition.
  • #1
milkism
118
15
Homework Statement
Find the impuls wavefunction phi(p) from the position wavefunction.
Relevant Equations
Look solution.
I have this following Gaussian wavefunction.
1705233351985.png

I found the constant C to be $$\sqrt{\sqrt{\frac{2 \alpha}{\pi}}}$$.
Now they're asking me to find the normalized impuls wavefunction $$\phi(p)$$. I tried to use the fourier transform relation
$$\phi (p) = \int e^{-\frac{i ( p x)}{\hbar}} \Psi (x,t=0) dx$$
and i got a long answer
$$\sqrt{\sqrt{\frac{2 \alpha}{\pi}}} \sqrt{\frac{\pi}{\alpha}} e^{-\frac{q^2}{4\alpha} + \frac{pq}{2 \alpha \hbar} - \frac{p^2}{4 \alpha \hbar ^2}}$$
Is there an other way to solve this? Because next question is to find the expectation value of position from the normalized impuls wavefunction, which is going to be very hard.
 
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  • #2
Is there a better way to find impuls wavefunctions from position wavefunctions?
 
  • #3
Any other way will of course give the same result.
 
  • #4
milkism said:
I found the constant C to be
How ? [edit] never mind o:)
milkism said:
Because next question
Can you please post the complete problem statement ?

##\ ##
 
  • #5
BvU said:
How ?
Can you please post the complete problem statement ?

##\ ##
$$\int_{-\infty}^{\infty} \Psi ^{*} \Psi dx =1, \int_{-\infty}^{\infty} C^2 e^{-2 \alpha x^2} dx = C^2 \sqrt{\frac{\pi}{2\alpha}} = 1$$
 
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  • #6
Calculate the corresponding normalized wave function φ(p) in momentum space. Explicitly compute, based on the knowledge of φ(p), the expectation value 〈x〉.
 
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  • #7
milkism said:
and i got a long answer
##e^{-{1\over 4\alpha}\left(q-p\right )^2}\ ## doesn't look all that bad to me ...
a peak around p = q, so the exercise will probably end up at something moving to the right with momentum ##q##

(did you check there is no ##i## in there ?)

The exercise reminded me of the treatment in Merzbacher, QM 2nd ed (1970 !) chapter 2.2

Next step was $$\psi(x,t) = {1\over \sqrt{2\pi}}\int_{-\infty}^{+\infty} \phi(k) e^{i(kx-\omega t}) dk$$ but I'm too rusty to comfortably work that out ( i.e. ##\omega(k)## )

##\ ##
 
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FAQ: Quantum Mechanics I, finding impuls wavefunction.

What is an impulse wavefunction in quantum mechanics?

An impulse wavefunction, often referred to as a delta function or Dirac delta function, is a mathematical function that represents an infinitely sharp peak at a single point. In quantum mechanics, it is used to model a particle that is precisely localized in space at a given moment in time.

How do you represent an impulse wavefunction mathematically?

Mathematically, an impulse wavefunction is represented by the Dirac delta function, denoted as δ(x). This function has the property that it is zero everywhere except at x = 0, where it is infinitely large, and it integrates to one over the entire space, i.e., ∫δ(x) dx = 1.

What is the significance of the impulse wavefunction in quantum mechanics?

The impulse wavefunction is significant because it represents a state of perfect localization in position space. This idealized concept helps in understanding the principles of quantum mechanics, particularly in the context of the Heisenberg uncertainty principle, which states that a particle cannot be perfectly localized in both position and momentum simultaneously.

How do you find the momentum wavefunction from an impulse wavefunction?

To find the momentum wavefunction from an impulse wavefunction, you perform a Fourier transform on the position wavefunction. For an impulse wavefunction represented by δ(x), the Fourier transform yields a constant function in momentum space, indicating that the particle has an equal probability of having any momentum value.

What are the practical applications of the impulse wavefunction in quantum mechanics?

Impulse wavefunctions are used in various practical applications, including the analysis of scattering problems, the study of propagators, and the formulation of Green's functions in quantum mechanics. They also play a crucial role in signal processing and in the mathematical formulation of quantum field theory.

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