- #1
neelakash
- 511
- 1
I have started my course (a bit earlier than my university---that is why I am reading myself) in Quantum Physics.And I got the following queries to clarify:
Sometimes we need to accept seemingly contradictory features...I want to discuss them and clarify...
(i)Can we conceive a stationary (at rest) particle in QM?If so,do we need to associate a wave-function with it?
What I think:Qm is not worried about this.Even if it is possible,there will be no physically interesting situation...
(ii)In the expression of a(p),which is the Fourier transform of Ψ(x),time t is explicit.Yet, a(p) does not depend on time.
What I think:I do not understand why.
(iii) We know: <x>=∫(Ψ* x Ψ) dx and <p>=(ˉh/i) ∫[Ψ* (∂/∂x) Ψ] dx
where (h/2π)= ˉh
Why is Ψ* in the front place and not the Ψ?What would be the problem if the formula were:
<x>=∫(Ψ x Ψ*) dx and <p>=(ˉh/i) ∫[Ψ (∂/∂x) Ψ*] dx
What I think: I do not understand.
Sometimes we need to accept seemingly contradictory features...I want to discuss them and clarify...
(i)Can we conceive a stationary (at rest) particle in QM?If so,do we need to associate a wave-function with it?
What I think:Qm is not worried about this.Even if it is possible,there will be no physically interesting situation...
(ii)In the expression of a(p),which is the Fourier transform of Ψ(x),time t is explicit.Yet, a(p) does not depend on time.
What I think:I do not understand why.
(iii) We know: <x>=∫(Ψ* x Ψ) dx and <p>=(ˉh/i) ∫[Ψ* (∂/∂x) Ψ] dx
where (h/2π)= ˉh
Why is Ψ* in the front place and not the Ψ?What would be the problem if the formula were:
<x>=∫(Ψ x Ψ*) dx and <p>=(ˉh/i) ∫[Ψ (∂/∂x) Ψ*] dx
What I think: I do not understand.