- #1
hmvince
- 44
- 0
Hey everyone!
Recently got a question in maths which asks:
"Use integral calculus to find the equation of the quartic that has stationary points of inflection at (1, 23) and (3, 15) and a y-intercept of 24"
This means that the second derivative has the form (as inflection points are x-intercepts in the second derivative):
f''(x) = k(x-1)(x-3)
I integrate this and get an answer for f'(x), all fine and dandy. But then I say, since there are two stationary points, f'(1) = 0, and f'(3) = 0, and it all breaks down!
Is it even possible to have a quartic with TWO stationary points of inflection, or am I just screwing something up (haha)?
Cheers.
Recently got a question in maths which asks:
"Use integral calculus to find the equation of the quartic that has stationary points of inflection at (1, 23) and (3, 15) and a y-intercept of 24"
This means that the second derivative has the form (as inflection points are x-intercepts in the second derivative):
f''(x) = k(x-1)(x-3)
I integrate this and get an answer for f'(x), all fine and dandy. But then I say, since there are two stationary points, f'(1) = 0, and f'(3) = 0, and it all breaks down!
Is it even possible to have a quartic with TWO stationary points of inflection, or am I just screwing something up (haha)?
Cheers.