- #1
LostInToronto
- 6
- 0
I've already posted this question in the advanced physics forum, but I really think it should go here. My apologies for the double posting.
If we are given a uniformly charged solid sphere with total charge Q and radius R, then the volume charge density rho is given by
[tex]\rho = \frac{Q}{\frac{4}{3} \pi R^3}[/tex].
My question is: How do we express the surface charge density sigma of a spherical shell of infinitesimal width dr, located within this solid sphere?
I keep reading that
[tex]\sigma = \rho dr[/tex]
but I really don't understand why this is the case. If someone could help clear this up, I'd really appreciate it.
Homework Statement
If we are given a uniformly charged solid sphere with total charge Q and radius R, then the volume charge density rho is given by
[tex]\rho = \frac{Q}{\frac{4}{3} \pi R^3}[/tex].
My question is: How do we express the surface charge density sigma of a spherical shell of infinitesimal width dr, located within this solid sphere?
Homework Equations
The Attempt at a Solution
I keep reading that
[tex]\sigma = \rho dr[/tex]
but I really don't understand why this is the case. If someone could help clear this up, I'd really appreciate it.