Question about Coloumb's law notation and math in two different textbooks

In summary, the discussion focuses on the differences in notation and mathematical presentation of Coulomb's law as found in two different textbooks. It examines how each text approaches the formula, variables, and the underlying concepts, highlighting any discrepancies or unique interpretations that may affect understanding for students.
  • #1
Selectron09
20
3
TL;DR Summary
Trying to understand mathematically how Jackson Classical Electrodynamics and Griffiths both describe coloumb's law equation
I am currently taking Electricity and Magnetism I for Graduate school and we are of course using Jackson Classical Electrodynamics 3e. I am used to Griffiths from undergrad and intro physics in that they describe it:
1694274144420.png


But Jackson modifies the notation to include a cube of the magnitude in the denominator:
1694274419944.png


I have tried to wrap my head around it. My professor just said it makes it "less mathematically akward" which is fine. Can someone take me stepwise line by line why these two are the same? I would really appreciate it. I want to be sure that I am getting used to the notation early of Jackson as I hear that's the trickiest part. It's not "new" physics!
 

Attachments

  • 1694273807045.png
    1694273807045.png
    19.9 KB · Views: 63
  • 1694274310407.png
    1694274310407.png
    19.1 KB · Views: 61
Last edited by a moderator:
Physics news on Phys.org
  • #2
Of course, Jackson has it in the clearest way. It's just giving the force between two point charges at given positions. Of course it's the same as in Griffiths's book. You only have to look up the definition of ##\vec{r}##. That becomes clear by rewriting the Jackson formula in the following way
$$\vec{F}=\frac{k q_1 q_2}{|\vec{x}_1-\vec{x}_2|^2} \frac{\vec{x}_1-\vec{x}_2}{|\vec{x}_1-\vec{x}_2} \equiv \frac{k q_1 q_2}{r^2} \hat{r},$$
where ##\vec{r}=vec{x}_1-\vec{x}_2## and ##\hat{r}=\vec{r}/|\vec{r}|##.

I'd also have written ##\vec{F}_1## for the force, because it's the force on charge 1 due to the presence of charge 2. Of course, you get ##\vec{F}_2=-\vec{F}_1## as it should be for static fields.
 
  • Like
Likes Selectron09
  • #3
Thankyou very much. That was amazingly helpful and gets me on the right track now as I continue through the reading. Much gratitude and I shall not hesitate to come back again after I've struggled through it.
 
  • Like
Likes PhDeezNutz and vanhees71
  • #4
The form ##{\bf r}/r^3## is more convenient for taking vector derivatives like grad, div, curl.
 
  • #5
You can also work in, e.g., spherical coordinates. Then you work with vector components wrt. the according (position-dependent) vectors ##\vec{e}_r##, ##\vec{e}_{\vartheta}##, and ##\vec{e}_{\varphi}##.
 

FAQ: Question about Coloumb's law notation and math in two different textbooks

What is Coulomb's Law, and how is it typically represented in textbooks?

Coulomb's Law describes the electrostatic force between two charged objects. It is typically represented as \( F = k_e \frac{|q_1 q_2|}{r^2} \), where \( F \) is the magnitude of the force, \( k_e \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the magnitudes of the charges, and \( r \) is the distance between the charges.

Why do different textbooks use different notations for Coulomb's Law?

Different textbooks may use different notations based on the author's preference, the educational level of the target audience, or regional conventions. For example, some textbooks might use \( k \) instead of \( k_e \) for Coulomb's constant, or they might represent the charges and distance differently.

How do I reconcile differences in Coulomb's Law notation between textbooks?

To reconcile differences, focus on understanding the fundamental concepts and relationships described by the equations. Identify the variables and constants used in each textbook and how they correspond to each other. This will help you translate between the different notations and ensure you understand the underlying physics.

What should I do if the numerical values for Coulomb's constant differ between textbooks?

If you encounter different numerical values for Coulomb's constant, check the units and context in which they are used. Some textbooks might use different unit systems (e.g., SI units vs. CGS units), leading to different numerical values. Ensure you are consistent with the units throughout your calculations.

Can the differences in notation affect my problem-solving in physics?

Differences in notation should not fundamentally affect your problem-solving as long as you understand the concepts and can translate between notations. However, being aware of the notation differences is important to avoid confusion. Always double-check the definitions and units provided in the specific textbook you are using.

Similar threads

Replies
9
Views
2K
Replies
6
Views
2K
Replies
4
Views
2K
Replies
2
Views
2K
Replies
2
Views
2K
Replies
39
Views
4K
Replies
14
Views
3K
Back
Top