- #1
mathplease
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The instantaneous energy density of a region of space of an EM wave is:
u = [tex]\epsilon[/tex]0E2 [J/m^3]
hence the average energy density is:
uavg = (1/2)[tex]\epsilon[/tex]0E02 [J/m^3]
uavg = <S> / c [J/m^3]
Is this equal to the wave's average http://en.wikipedia.org/wiki/Radiation_pressure" measured in [Pa] if the radiation is fully absorbed?
Prad= <S> / c [Pa]
My physics lecturer said these are not the same as one is measured in [J/m^3] and one is in [Pa], which seems clearly wrong to me but I'm worried I may have a misunderstanding in these concepts. Any confirmation or clarity is appreciated.
u = [tex]\epsilon[/tex]0E2 [J/m^3]
hence the average energy density is:
uavg = (1/2)[tex]\epsilon[/tex]0E02 [J/m^3]
uavg = <S> / c [J/m^3]
Is this equal to the wave's average http://en.wikipedia.org/wiki/Radiation_pressure" measured in [Pa] if the radiation is fully absorbed?
Prad= <S> / c [Pa]
My physics lecturer said these are not the same as one is measured in [J/m^3] and one is in [Pa], which seems clearly wrong to me but I'm worried I may have a misunderstanding in these concepts. Any confirmation or clarity is appreciated.
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