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Drteeth
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Question about nondisjunction - help please!
My question is related specifically to Trisomy 21. Let's consider spermatogenisis. I know that nondisjunction can occur in either anaphase 1 or anaphase 2, but I was wondering what the outcome of the number of chromosomes is in each of the 4 resulting sperm cells? From what I can see, if the nondisjunction event occurs during anaphase 1, there will be 2 resulting cells with n+1 chromosomes (24) and 2 cells with n-1 (22) chromosomes (where n = the normal haploid number). However, when the nondisjunction events occurs during anaphase 2 I see one n+1 cell resulting, one n-1 cell, and two normal cells with n chromosomes.
Please tell me if this analysis is correct. If not, please give me the correct answer.
Thank you for your help!
My question is related specifically to Trisomy 21. Let's consider spermatogenisis. I know that nondisjunction can occur in either anaphase 1 or anaphase 2, but I was wondering what the outcome of the number of chromosomes is in each of the 4 resulting sperm cells? From what I can see, if the nondisjunction event occurs during anaphase 1, there will be 2 resulting cells with n+1 chromosomes (24) and 2 cells with n-1 (22) chromosomes (where n = the normal haploid number). However, when the nondisjunction events occurs during anaphase 2 I see one n+1 cell resulting, one n-1 cell, and two normal cells with n chromosomes.
Please tell me if this analysis is correct. If not, please give me the correct answer.
Thank you for your help!
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