Question about photocell experiment

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In summary, the conversation discusses the relationship between voltage and photoelectric current in a set up with a power supply, photocell, and ammeter. The book suggests that the current gradually increases as the voltage increases until it reaches a saturated current. However, the exercise suggests that the current does not increase because it is not influenced by the dry cell, but by radiation. The correct explanation is that the applied voltage attracts the electrons knocked off by the light, and at a high enough voltage, all the free electrons flow to the collector, resulting in a saturated current. To increase the current, the intensity of the light must be increased.
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Clara Chung
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Consider a set up with a power supply(dc voltage) ,and a photocell (metal plate + collector) ,and an ammeter. Frequency of light is constant.

When V gradually increases from 0 (anode linked to the collector, anode to the metal plate), the photoelectric current is said to be increasing until it reaches the saturated current. (from my book)

But from my exercise, it says it won't increase because the current is not contributed by the dry cell, but by radiation. Once the photoelectrons are emitted, they tend to go round the circuit(because there is a potential no matter its value) and return to the illuminated metal. The dry cell cannot increase the number of photoelectrons.

Which one is correct?
 
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The light hitting the photocell knocks some electrons off of the metal in random directions. The externally applied voltage (from the dry cell in your description) attracts the electrons. At low applied voltage there is not enough electric field strength to attract all the electrons that were knocked off. A higher applied voltage will attract more of the free electrons, as shown by the higher current. Eventually, with a high enough applied voltage, all the free electrons flow to the collector in the photocell. This is the "saturated current" the book refers to. To get a higher current you need to increase the light intensity (more photons per second) to knock off more electrons.
 
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Related to Question about photocell experiment

1. What is a photocell experiment?

A photocell experiment is an experiment that involves using a photocell, also known as a photoelectric cell, to study the properties of light and its interaction with matter. A photocell is a device that converts light energy into electrical energy.

2. How does a photocell work?

A photocell consists of a photoemissive material, such as metal, that releases electrons when exposed to light. These electrons are then collected by a positively charged electrode, creating an electrical current. The intensity of the light affects the number of electrons released, thus affecting the current produced.

3. What can be measured in a photocell experiment?

A photocell experiment can measure various properties of light, such as its intensity, wavelength, and polarization. It can also be used to study the effects of different materials on the absorption and emission of light.

4. What is the purpose of a photocell experiment?

The purpose of a photocell experiment is to better understand the behavior of light and its interaction with matter. It can also be used to study the properties of different materials and their potential applications in technology.

5. What are some real-world applications of photocells?

Photocells have various applications in everyday life, such as in solar panels, light sensors, and photocopiers. They are also used in scientific research, for example, in measuring the intensity of light in different environments or in studying the properties of different materials.

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