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The_ArtofScience
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I've been drawn to this expression for a long time.
Anyway, my question is - is the derivative of e^x exact? That is with absolute precision, the derivative of e^x is EXACTLY e^x?
Sorry if this seems like a silly question, I would really like to know if my math instructor is right on this one
I remember the argument:
lim h-->0 e^x+h - e^x/ h
What about the constant e? Is it approximate or absolutely precise?
Say you have a base, b.
Then lim q->0 ([b^1+q -b]/q) = b, which through some adjustments gives e = lim n-> infinity (1 +1/n)^n
Anyway, my question is - is the derivative of e^x exact? That is with absolute precision, the derivative of e^x is EXACTLY e^x?
Sorry if this seems like a silly question, I would really like to know if my math instructor is right on this one
I remember the argument:
lim h-->0 e^x+h - e^x/ h
What about the constant e? Is it approximate or absolutely precise?
Say you have a base, b.
Then lim q->0 ([b^1+q -b]/q) = b, which through some adjustments gives e = lim n-> infinity (1 +1/n)^n
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