- #1
hello478
- 165
- 14
- Homework Statement
- image below
- Relevant Equations
- energy equations
My attempt:
my answer was b
correct answer is d
because before the release they are stationaryBvU said:Can you explain why you picked b ?
Do you know the expression for kinetic energy?
"Conserved" means "it is the same" throughout whatever is going on. Before release the sum of kinetic energies is zero because neither block is moving. If, as you claim, this sum is conserved, then neither block should be moving after release. Do you think that is the case?hello478 said:so that the total KE is conserved...
Why would kinetic energy be conserved? This would mean the blocks just remain stationary as kinetic energy is non-negative.hello478 said:because before the release they are stationary
and it is elastic collision, maybe...
so the kinetic energies would add upto 0
so that the total KE is conserved...
BvU said:Do you know the expression for kinetic energy?
It sounds to me that based upon your many posts with seemingly little thought behind your attempts that what you really need to do before attempting these problems is to sit down with your book and try to understand the theory behind the problems first. Otherwise you will just be shooting wildly with your answers.hello478 said:oh ok so, the velocities direction would not be considered.... thats the only thing i understand uptill now
ill try to do that, though i sort of know what the book says... physics is just not my thing so its difficult for me to graspOrodruin said:It sounds to me that based upon your many posts with seemingly little thought behind your attempts that what you really need to do before attempting these problems is to sit down with your book and try to understand the theory behind the problems first. Otherwise you will just be shooting wildly with your answers.
Tip (that worked for me): while reading, invent tough exercises you could test your classmates with.hello478 said:ill try to do that, though i sort of know what the book says... physics is just not my thing so its difficult for me to grasp
when i read the book, everything is so easy until the questions blow my mind...
ok ill try to do that too, but i dont have much time till my exams...BvU said:Tip (that worked for me): while reading, invent tough exercises you could test your classmates with.
and im currently doing physics AS levels and biology A levelsBvU said:(what's yours?)
The potential energy stored in a spring when it is compressed or stretched is given by the formula \( \frac{1}{2} k x^2 \), where \( k \) is the spring constant and \( x \) is the displacement from the equilibrium position.
The mass of the blocks affects the system's kinetic energy. When the spring is released, the potential energy stored in the spring is converted into kinetic energy of the blocks. The kinetic energy of each block can be determined using the conservation of energy and momentum principles.
If the spring is ideal and there is no friction, the total mechanical energy of the system is conserved. This means that the sum of the potential energy in the spring and the kinetic energy of the blocks remains constant over time.
The velocities of the blocks after the spring is released can be calculated using the conservation of momentum and the conservation of energy principles. By setting up equations for both conservation laws, you can solve for the velocities of the two blocks.
The spring constant \( k \) affects the amount of potential energy stored in the spring for a given displacement. A higher spring constant means a stiffer spring, which stores more energy for the same displacement. This will result in higher kinetic energy of the blocks when the spring is released, assuming no energy losses.