Question about the limits of integration in a change of variables

In summary, the topic discusses the importance of correctly determining the limits of integration when performing a change of variables in calculus. It emphasizes that the new limits must correspond to the transformed variables and outlines the need for careful consideration of the relationship between the original and new variables to ensure accurate results in integrals.
  • #1
Chenkel
482
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Hello everyone,

If I have an integral ##\int_0^r \sqrt{(r^2 - x^2)}dx## and I'm integrating across the first quadrant to get the area of the first quater of a circle.

And I change variables with ##x = r\cos{\theta}## and ##dx = -{r}\sin{\theta}{d\theta}##

And I form a new integral that's ##-\int_{\frac {\pi}{2}}^0 \sqrt{(r^2 - ({r\cos{\theta}})^2)}r\sin{\theta}{d\theta}##

Did I calculate the limits of integration correctly? Because when x is 0 the arc from the x axis to y axis is ##\frac {\pi}{2}## and when x is r the arc is 0.

I got positive ##{\frac {\pi} 4} r^2## for the first quadrant area (1 quarter of the circle using these equations) so I imagine my approach should be working but I wonder about the rigorourness of the change of limits of integration in my approach.

Let me know what you think!

Thank you!
 
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  • #2
Yes that's fine. Note that, by definition, ##\int_a^b = -\int_b^a##. You could have sorted out the limits that way. In general, using a decreasing function in your substitution is fine.

Note that you could have used sine instead of cosine. Which might have been slightly simpler.
 
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  • #3
PeroK said:
Yes that's fine. Note that, by definition, ##\int_a^b = -\int_b^a##. You could have sorted out the limits that way. In general, using a decreasing function in your substitution is fine.

Note that you could have used sine instead of cosine. Which might have been slightly simpler.
Thank you!
 

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