Question about vector coordinates

In summary: What is the length of \mathbf{x}(t) and what does it mean for the point to be on the line segment AB?In summary, the problem involves finding the length of the line segment AC, which is related to the vector AB. In order to find AC, it is not correct to simply multiply AB by 2/5. Instead, the origin must be involved in the calculation. Drawing a sketch can help understand the problem better. A weighted average of vectors can be used to find AC, where the weights of the average correspond to the lengths of AC and CB. Additionally, considering the equation \mathbf{x}(t) = (1-t)\mathbf{a} + t\mathbf{b}
  • #1
homeworkhelpls
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Homework Statement
Find C position vector
Relevant Equations
none
1666203644182.png

here i found AB to be (-3, 2) and then i thought to do 2/5 multiplied by AB to find AC, however this is incorrect and instead i would have to involve the origin. Why and how can i involve the origin?
 
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  • #2
The problem statement in combination with your attempt are confusing for me. Can you upload a drawing of this line please? Thanks.
 
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  • #3
homeworkhelpls said:
here i found AB to be (-3, 2) and then i thought to do 5/2 multiplied by AB to find AC
I think AB here is supposed to be the length of the line segment connecting points A and B. It's not the vector ##\mathbf{b}-\mathbf{a}##, though it is related. And I think you meant you multiplied by 2/5, not 5/2. Or at least that would somewhat make sense.

Anyways, draw a sketch. I think it'll help you understand what the problem is asking for.
 
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  • #4
Do you know how to calculate a weighted average of vectors ##a## and ##b## so that ##a## gets 3/5 of the weight and ##b## gets 2/5? Would that point be on the AB line? How do the lengths of the AC and CB relate to the weights of the average?
 
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  • #5
Consider [itex]\mathbf{x}(t) = (1-t)\mathbf{a} + t\mathbf{b}[/itex] for [itex]0 \leq t \leq 1[/itex]
 
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