Question on acceleration and string-HELP

In summary: The Wizard of Oz, is transported to Oz by a tornado. She is pulled along with the tornado until she is close to the ground, at which point the tornado stops and she falls to the ground. If Dorothy's weight (and that of the tornado) are constant, how far will she travel before she stops?In summary, if the weight and velocity of the object are constant, Dorothy will travel a distance equal to her weight before she stops.
  • #1
Aleksandar
10
0
I need big help on this question guys:

One test for the effects of the acceleration of gravity is to tie a set of weights to a string, with the second lowest searated from the lowes by L0, the third lowest from the second lowest by L1, and so forth, and to then drop the string. Suposing that free fall corresponds to motion with constant acceleration, how would separations L1, L2,...,Ln (where n is the number of weights) be related to L0 if the sounds made by the weights as they land form a steady beat? The lowest weight starts at the surface onto which the other weights fall.

I NEED HUGE HELP FOR THIS QUESTION
PLEASE HELP ME
If you can also explain me into more detail so I can get it easily.
 
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  • #2
Since the acceleration of gravity is constant, what is the difference between having strings between the objects, and having rigid poles? Is there any difference? If not, why not?

What is the kinematic equation that relates the acceleration of an object to its velocity and position?
 
  • #3
I still don't get it. Can you explain the question in detail. Can you guys please give me more hints if possible. PLEASE
 
  • #4
MASSIVE HINT: Is the distance between the weights going to change? Note that as berkeman said, the acceleration experienced by each object is constant and equal. Note also that all the weights begin from rest (vi=0) and the bottom weight starts on the surface (x0=0)
 
  • #5
Aleksandar said:
I still don't get it. Can you explain the question in detail. Can you guys please give me more hints if possible. PLEASE

What happens if you have four weights separated by strings of equal length on a horizontal surface, and then push them together at a constant speed (i.e., no acceleration)? You get Hup two three four, or BONG BONG BONG BONG, equally spaced sounds. This is related to the equation of motion for constant velocity and distance: x = vt.

What is the equivalent equation of motion for constant acceleration, and how does this change the situation for the four weights?

Dorothy
 

FAQ: Question on acceleration and string-HELP

What is acceleration?

Acceleration is the rate of change of velocity over time. It is a vector quantity, meaning it has both magnitude and direction. Acceleration can be positive (speeding up), negative (slowing down), or zero (constant speed).

How is acceleration calculated?

Acceleration can be calculated by dividing the change in velocity by the change in time. The equation for acceleration is a = (vf - vi)/t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.

What is the difference between average and instantaneous acceleration?

Average acceleration is the overall change in velocity over a period of time, while instantaneous acceleration is the acceleration at a specific moment in time. Instantaneous acceleration can vary within the period of time that is used to calculate average acceleration.

How does a string affect acceleration?

A string can affect acceleration by providing a force that can either increase or decrease the acceleration of an object. If a string is attached to an object and pulled in the direction of motion, it can increase the acceleration. If a string is attached to an object and pulled in the opposite direction of motion, it can decrease the acceleration.

Can the mass of an object affect its acceleration when attached to a string?

Yes, the mass of an object can affect its acceleration when attached to a string. According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This means that a larger mass will experience a smaller acceleration when attached to a string compared to a smaller mass.

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