- #1
jayadds
- 42
- 0
Given the following information: a 6.10m long snorkel, density of air = 1.21 kg/m^3, atmospheric pressure = 1.013 x 10^5 P, g = 9.8 m/s^2 and density of seawater = 1.03 x 10^3 kg/m^3, how would you calculate the pressure outside the scuba diver's lungs?
Would it be anything to do with this equation?
pressure outside lungs = atmospheric pressure + (density of seawater)*g*(6.10)
Thanks.
Would it be anything to do with this equation?
pressure outside lungs = atmospheric pressure + (density of seawater)*g*(6.10)
Thanks.