Question on liouville's theorem

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In summary, Liouville's theorem states that the phase space density moves as an incompressible fluid. This contradicts the concept of chaos, which says that points in phase space spread out with time. However, in particle accelerators, Liouville's theorem is obeyed and chaos does not occur.
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RedX
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Liouville's theorem says that the phase space density moves as an incompressible fluid.

In other words, if you follow a point in phase space, the number of points surrounding that point will always be the same.

Does this contradict the concept of chaos, which says that points in phase space spread out with time?
 
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I figured out the answer, but is the paper that you linked to describing how to turn lead into gold?

How does that work? If you accelerate a proton near a nucleus, then the beam proton changes into a neutron beam and emits a +1 pion, which is captured by a neutron in the nucleus, turning it into a proton?

What's the energy of the beam proton? I assume less than .2 GeV because we're talking about hadrons and not free quarks and gluons? What happens to the neutron beam: how is it stopped (what particle process stops it)?

Since lead has a greater atomic number than gold, then you would have to do the converse process - shoot neutron beams into lead. How do you accelerate a neutron beam?

Wouldn't the resulting atom be imbalanced as far as proton/neutron ratio? Or can you send a beam of neutrons and the neutrons just stick to the nucleus without inducing a change that'll turn a proton into a neutron? Or do you send a beam of neutrons, and a neutron attaches to the nucleus, which will later beta decay (so a weak process instead of a strong process), giving you an extra proton?

And a little less serious question: should I be worried about the commodity price of gold?
 
  • #4
RedX said:
I figured out the answer, but is the paper that you linked to describing how to turn lead into gold? ...And a little less serious question: should I be worried about the commodity price of gold?
Multi-MeV proton beams in particle accelerators do obey Liouvill's theorem phase space predictions during acceleration, and exhibit phase space growth with chaos. But unfortunately it is both difficult and expensive to convert platinum (Z=78) or mercury (Z=80) to gold (Z=79) using a particle beam.

Bob S.
 
  • #5
Bob S said:
Multi-MeV proton beams in particle accelerators do obey Liouvill's theorem phase space predictions during acceleration, and exhibit phase space growth with chaos. But unfortunately it is both difficult and expensive to convert platinum (Z=78) or mercury (Z=80) to gold (Z=79) using a particle beam.

Bob S.

The beams are collimated one proton at a time aren't they? Why would there be chaos in such a situation?

Multi-MeV: thanks. Is that the typical range of protons under a Linac? Electrons would be the same range right, or would they brem even more than protons, so won't reach the multi-MeV range?

Platinum is worth more than gold, so you wouldn't want to turn it into gold anyway. So maybe turn whatever is Z=77 into platinum would be good.

On Wikipedia's transmutation page, there's the following quotation about converting gold into lead:

"It would be easier to convert gold into lead via neutron capture and beta decay by leaving gold in a nuclear reactor for a long period of time."

Is this better than shooting multi-MeV protons at the gold hoping to induce a transformation of a neutron into a proton via pion exchange? There's a big difference between shooting a neutron trying to induce neutron capture and shooting a proton trying to induce a transmutation of a neutron into a proton. I guess what's bothering me is if you shoot a neutron at the gold nucleus, who says neutron capture will happen instead of the neutron causing a proton in the nucleus to change into a neutron?
 
  • #6
RedX said:
The beams are collimated one proton at a time aren't they? Why would there be chaos in such a situation?
In a 100-milliamp proton beam bunched at 400 MHz, there are roughly 1.5 billion protons confined by electric and magnetic fields into a bunch about 1 centimeter long. The electric and magnetic fields preserve phase space (six dimensional) as the protons are accelerated, but RF noise, magnet misalignment, and intra-beam scattering does cause the phase space to grow. A lot of opportunity for chaos.

Bob S
 
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FAQ: Question on liouville's theorem

What is Liouville's theorem?

Liouville's theorem, also known as Liouville's equation, is a fundamental concept in classical mechanics that states that the phase space of a conservative system is conserved over time. This means that the distribution of positions and momenta of particles in a system will remain constant as the system evolves.

How is Liouville's theorem related to Hamiltonian mechanics?

Liouville's theorem is a consequence of Hamiltonian mechanics, which is a mathematical formalism used to describe the dynamics of conservative systems. Hamiltonian mechanics is based on the principle of conservation of energy and is used to solve problems in classical mechanics.

What are the applications of Liouville's theorem?

Liouville's theorem has various applications in physics and engineering, such as in celestial mechanics, statistical mechanics, and fluid dynamics. It is also used in the study of chaos theory and the behavior of complex systems.

What are the assumptions of Liouville's theorem?

Liouville's theorem assumes that the system is conservative, meaning that it does not lose or gain energy, and that it is deterministic, meaning that the future state of the system can be determined from its current state with certainty.

Are there any limitations to Liouville's theorem?

Liouville's theorem is based on classical mechanics and does not hold in quantum mechanics, where the uncertainty principle states that the position and momentum of a particle cannot be measured simultaneously with absolute precision. Additionally, Liouville's theorem assumes that the system is isolated and does not take into account any external forces or interactions.

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