Question on Primitive Roots and GCDs

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In summary, the content discusses the relationship between primitive roots and greatest common divisors (GCDs) in number theory. It explores how primitive roots can be determined based on the properties of modular arithmetic and the conditions under which a number has a primitive root. The discussion includes examples and clarifications on how GCDs play a role in finding primitive roots for various integers.
  • #1
Albert01
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I have a question about a certain fact from the book of Nussbaumer "Fast Fourier Transform and Convolution Algorithms" in the chapter of Number-theoretic transformation. I have quoted the relevant passage once.

There it says:

##(g^t -1)S \equiv g^{Nt} - 1 \equiv 0 \text{ mod } q \quad (1)##

Thus, ##S \equiv 0## provided ##g^t - 1 \not\equiv 0 \text{ mod } q## for ##t \not\equiv 0 \text{ mod } N##. This implies that ##g## must be a root of unity of order ##N \text{ mod } q##, that is to say, ##g## must be an integer such that ##N## is the smallest nonzero integer for which ##g^N \equiv 1 \text{ mod } q##.

This quotation refers to ##q## being a prime number. But then it continues with a consideration of ##q## as a composite number. There it is stated:

Equation ##(1)## implies not only that ##g## is a root of order ##N \text{ mod } q##, but also, since ##q## is composite, that ##[(g^t-1), q] = 1##.
Questions:

  • My question is actually "only" how one comes to the conclusion that from equation ##(1)## follows ##[(g^t-1), q] = 1##, when ##q## is composite; and what benefit you get out of it.
  • A second question that follows from this would then be whether ##[(g^t-1), q] = 1## (must) hold for ##t=1,...,N-1##?
 
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  • #2
Albert01 said:
I have a question about a certain fact from the book of Nussbaumer "Fast Fourier Transform and Convolution Algorithms" in the chapter of Number-theoretic transformation. I have quoted the relevant passage once.

There it says:
This quotation refers to ##q## being a prime number. But then it continues with a consideration of ##q## as a composite number. There it is stated:

Albert01 said:
Questions:

  • My question is actually "only" how one comes to the conclusion that from equation ##(1)## follows ##[(g^t-1), q] = 1##, when ##q## is composite; and what benefit you get out of it.
It doesn't fillow. It is an additional requirement in oder to have the same conclusion.
Albert01 said:
  • A second question that follows from this would then be whether ##[(g^t-1), q] = 1## (must) hold for ##t=1,...,N-1##?
Isn't ##t## fixed?
 
  • #3
Hi @martinbn,

martinbn said:
It doesn't fillow. It is an additional requirement in oder to have the same conclusion.

Can you please explain this a little bit more?



If ##\text{gcd}(g^t-1,q) = 1## we can write ##(g^t-1) \cdot x + q \cdot y = 1##. On the other hand, we have ##g^t-1 \not\equiv 0 \text{ mod } q##, which we can write as ##g^t-1 \neq 0 + c \cdot q##. I don't see now how far you get to the same conclusion.



Should I add more info (to the passage from the textbook)?
 
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