Question on Silver Chloride (gravimetric analysis)

In summary, the second sample will contain a slightly lower percent chloride than the first sample due to the decomposition of silver nitrate. There is no measurable difference.
  • #1
Renge Ishyo
282
1
Forgive me for asking such a broad question, but does anybody know by how much (on average) oxygen discoloration will affect the percent chloride obtained from the precipitation of chloride from a sample using an aqueous solution of Silver Nitrate? More specifically, if the experimenter was to do this precipitation twice, the first time getting a white grey precipitate (no observeable purple/oxygen discoloration at all), and the second time the experimenter exposed his sample to light and received a purplish precipitate, by how much would the calculated percent Chloride result differ in the 2 samples?

As an example, say that I precipitated chloride from an unknown sample and obtained a pure white precipitate and calculated out that the original sample contained 56.4% Chloride in it. If the precipitate had been purple, by how much would I expect my result to deviate from 56.4% (or would it not deviate noticeably at all?)? I wish I could try this in the lab for myself, but my school is cheap and I only get to do this once (in case you are wondering, I received a white precipitate by obsessesively shielding my sample from the light, while everyone around me had purple precipitates because they didn't shield their samples from the light and I was wondering how much of a difference this would have made on the final result).

Thanks in advance for any help :)
 
Chemistry news on Phys.org
  • #2
You'll need to consider the equation for the decomposition and then apply the stoichiometry, but as for the percent error due to this reaction, I'm not quite sure how one would figure that out without knowing anything about the original unknown. What you can probably do though, is to find someway to determine the mass of the unknown sample minus the precipitate upon isolation, before you start drying it. That is some sensitive experimental procedure relating to weighing by difference; if you know what the mass of the precipitate had to be through such a gravimetric analysis, then you can determine the loss of the precipitate mass, which also includes the loss of water. Then perhaps solve a set of simultaneous equations.

Other ways, may involve time dependent regression analysis and so on, but we can circumvent all of this simply by minimizing the samples exposure to light. I don't quite know the literature values or any standard values that may have bee proposed through research for the magnitude of error due to such a decomposition.
 
  • #3
That is, minimize your determinate errors.
 
  • #4
Renge Ishyo said:
(snip)... that the original sample contained 56.4% Chloride in it. If the precipitate had been purple, by how much would I expect my result to deviate from 56.4% (or would it not deviate noticeably at all?)? (snip)

There's no measurable difference. If you've played with equilibrium constants, you can look at the reaction

2AgCl + 1/2 O2 = Ag2O + Cl2
(change in standard Gibbs free energy is around + 200 kJ/mol(Ag2), and make a few assumptions about chlorine and oxygen activities in the solution from which the precipitate formed (O2 activity is around 0.2, atmosphere; chlorine activity is going to be of the same order of magnitude as the amount of silver oxide formed (activity = 1)).

You also have the photolytic decomposition of AgCl to consider. This is the reaction producing the "purple" color of the precipitate, finely divided elemental silver. Same game as for the oxide formation, 100 kJ/mol, same chlorine activity estimate, same unit activities for the solid phases. Still a very small number.
 
  • #5
Thanks GCT and Bystander. I was wondering why nobody seemed to care if they left their samples exposed to the light (including the instructor). I guess if the error was small, that would explain why :wink:
 

FAQ: Question on Silver Chloride (gravimetric analysis)

1. What is silver chloride?

Silver chloride (AgCl) is a chemical compound composed of silver and chlorine atoms. It is a white, crystalline solid that is insoluble in water and most acids, but soluble in ammonia and concentrated solutions of potassium cyanide.

2. What is gravimetric analysis?

Gravimetric analysis is a quantitative analytical method used to determine the amount of a specific substance in a sample. It involves the separation of the substance from the sample by precipitation, filtration, and weighing the precipitate to calculate its mass and, therefore, the amount of the substance present.

3. How is silver chloride used in gravimetric analysis?

Silver chloride is commonly used in gravimetric analysis as a precipitating agent for the determination of halides (chloride, bromide, and iodide) in a sample. The silver chloride precipitate is then weighed to determine the amount of halide present in the sample.

4. What are the advantages of using silver chloride in gravimetric analysis?

Silver chloride is a highly insoluble compound, which means it can be easily separated from the sample without any loss. It also forms a well-defined and easily filterable precipitate, making it suitable for accurate and precise measurements. Additionally, the reaction between silver chloride and halides is highly specific, making it a reliable method for determining the amount of halides in a sample.

5. What are the limitations of using silver chloride in gravimetric analysis?

The main limitation of using silver chloride in gravimetric analysis is that it can only be used for the determination of halides. It is not suitable for the analysis of other substances, and its use is limited to samples with low concentrations of halides. Additionally, the presence of other interfering substances in the sample may affect the accuracy and precision of the results.

Similar threads

Back
Top