- #1
Mr.maniac
- 38
- 0
1. The probleas
statement, all variables and given/known data
Two stones are projected from the top of a tower 100m high each with velocity of 10m/s. One is projected upward while the other is projected downward. Find the ratio of velocity's by with which they strike the ground.
S= ut +1/2(a)(t)^2
(v)^2-(u)^2=2as
v=u+at[/B]
Let the stone projected upward be , body A
And the body projected downward be body B
For body A
(v)^2-(u)^2=2as
(v)^2-(100)=2(10)(100)
v=√(1900)
For body B before reaching max. height
(v)^2-(u)^2=2as
-(100)=(2)(10)(s)
5=s
For body B after reaching the max. height
(v)^2-(u)^2=2as
(v)^2=(2)(10)(105)
v=√(2100)
And I reached a dead end because
(10)(√21)/(10)(√19)
Ain't in the options
Please help
statement, all variables and given/known data
Two stones are projected from the top of a tower 100m high each with velocity of 10m/s. One is projected upward while the other is projected downward. Find the ratio of velocity's by with which they strike the ground.
Homework Equations
S= ut +1/2(a)(t)^2
(v)^2-(u)^2=2as
v=u+at[/B]
The Attempt at a Solution
Let the stone projected upward be , body A
And the body projected downward be body B
For body A
(v)^2-(u)^2=2as
(v)^2-(100)=2(10)(100)
v=√(1900)
For body B before reaching max. height
(v)^2-(u)^2=2as
-(100)=(2)(10)(s)
5=s
For body B after reaching the max. height
(v)^2-(u)^2=2as
(v)^2=(2)(10)(105)
v=√(2100)
And I reached a dead end because
(10)(√21)/(10)(√19)
Ain't in the options
Please help