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Yes, you're right. It is basically of the same difficulty as finding a relation in a group, or to show there is none. This is - as far as I know - not a trivial issue. I'm still thinking about @Buzz Bloom 's quest to solve it. At least the isomorphism ##\mathbb{Q}(\sigma_i) \cong \mathbb{Q}[x]/(x^5-x+1)## allows us to only consider polynomials and no fractions. I think the automorphism group is the whole ##\mathcal{Sym}(5)##, but I have no idea so far, how to prove the ##\sigma_i## actually behave like variables, or indeterminates, i.e. have no non-trivial relation ##f(\sigma_0,\ldots,\sigma_4)=0\,.##Stephen Tashi said:Your post #33 indicates that the simultaneous equations we are trying to solve in Galois theory are non-linear. This suggests that that the theory of groups and field automorphisms is useful in reasoning about the solutions of special types of non-linear equations.