- #1
Ser
- 8
- 0
I'm extremely confused in regards to many aspects concerning polyatomic ions. For one, am I correct in thinking that covalent polyatomic ions gain charges by having components dissociated? Ex. A and B are sharing an electron, A has a significantly greater hold, B is dissociated by something leaving A with the electron and the compound now having a - charge?
If my understanding of that is correct, here are some questions about polyatomic ion compounds:
1) Acids are covalent, right? Well how do they form, then? The polyatomic ion dissociates H+(s) from other compounds?
2) Well how does, say, Hydrobromic acid form? How can, in a covalent bond, an H+ and Br- come together? That seems ionic...they both dissociated from something else and happened to come together covalently but the electronegativity is even enough that the partial charge isn't significant so the + and - parts balance the charge?
3) Finally, how do ionic compounds with polyatomic ions work? If, say, Nitrate pulls off an electron from a group 1 element that element is now +1 and Nitratre is -2...how does that balance?
So confused..thanks in advance for bearing with my questions. I'm undoubtedly missing something here.
If my understanding of that is correct, here are some questions about polyatomic ion compounds:
1) Acids are covalent, right? Well how do they form, then? The polyatomic ion dissociates H+(s) from other compounds?
2) Well how does, say, Hydrobromic acid form? How can, in a covalent bond, an H+ and Br- come together? That seems ionic...they both dissociated from something else and happened to come together covalently but the electronegativity is even enough that the partial charge isn't significant so the + and - parts balance the charge?
3) Finally, how do ionic compounds with polyatomic ions work? If, say, Nitrate pulls off an electron from a group 1 element that element is now +1 and Nitratre is -2...how does that balance?
So confused..thanks in advance for bearing with my questions. I'm undoubtedly missing something here.