Questions about speed and motion of a toy car on a conveyor belt

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In summary, the discussion focuses on understanding the speed and motion dynamics of a toy car placed on a conveyor belt. It examines how the movement of the conveyor belt affects the car's speed, considering factors such as friction, acceleration, and the relative motion between the car and the belt. The analysis aims to clarify how these elements interact to influence the overall performance of the toy car in a controlled environment.
  • #1
Tonyapplepan
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New poster has been reminded to always show their work on schoolwork-type problems.
Homework Statement
A toy car moves from X to Y and back to X at a constant speed. If the conveyor belt moves with a constant speed in the same direction throughout, the round trip of the toy car takes time t1. If the conveyor belt remains stationary throughout, the round trip of the toy car takes time t2. What is the conclusion drawn if you compare t1and t2? How can I prove it? :)
Relevant Equations
Average speed=total distance/total time
A toy car moves from X to Y and back to X at a constant speed. If the conveyor belt moves with a constant speed in the same direction throughout, the round trip of the toy car takes time t1. If the conveyor belt remains stationary throughout, the round trip of the toy car takes time t2. What is the conclusion drawn if you compare t1and t2? How can I prove it? :)
3F7EA893-AC11-41BD-BABC-0C44352C81FD.jpeg
 
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  • #2
I assume X and Y are points fixed in the ground frame. (Perhaps there was a diagram?)
Per forum rules, please post an attempt.

"Relevant Equations" is for any standard equations you feel will be relevant, such as general equations for (constant) speed, time, and distance.
 
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  • #3
haruspex said:
I assume X and Y are points fixed in the ground frame. (Perhaps there was a diagram?)
Per forum rules, please post an attempt.

"Relevant Equations" is for any standard equations you feel will be relevant, such as general equations for (constant) speed, time, and distance.
Sorry that I didn’t gives a clear explanation,actually I think the diagram is quite misleading,as the motion of the car is from X to Y,and then from Y to X in straight line motion,but not moves in a circle
 
  • #4
Tonyapplepan said:
Sorry that I didn’t gives a clear explanation,actually I think the diagram is quite misleading,as the motion of the car is from X to Y,and then from Y to X in straight line motion,but not moves in a circle
Okay, it should be clear enough. What are you saying about ##t_1## and ##t_2##?
 
  • #5
PeroK said:
Okay, it should be clear enough. What are you saying about ##t_1## and ##t_2##?
t1 means the time travelled for car from X to Y then Y to X when the belt moves in uniform motion.t2 means the time travelled for car from X to Y then Y to X when the conveyor belt remains stationary throughout
 
  • #6
Tonyapplepan said:
t1 means the time travelled for car from X to Y then Y to X when the belt moves in uniform motion.t2 means the time travelled for car from X to Y then Y to X when the conveyor belt remains stationary throughout
I mean what's the question?
 
  • #7
PeroK said:
I mean what's the question?
The question is :A toy car moves from X to Y and back to X at a constant speed. If the conveyor belt moves with a constant speed in the same direction throughout, the round trip of the toy car takes time t1. If the conveyor belt remains stationary throughout, the round trip of the toy car takes time t2. What is the conclusion drawn if you compare t1and t2?
 
  • #8
Tonyapplepan said:
The question is :A toy car moves from X to Y and back to X at a constant speed. If the conveyor belt moves with a constant speed in the same direction throughout, the round trip of the toy car takes time t1. If the conveyor belt remains stationary throughout, the round trip of the toy car takes time t2. What is the conclusion drawn if you compare t1and t2?
And your conclusion is ...?
 
  • #9
Tonyapplepan said:
If the conveyor belt moves with a constant speed in the same direction throughout, the round trip of the toy car takes time t1.
Question 1: How can there be a "round trip" when the direction of the speed is "the same" throughout?
Question 2: Is this constant speed relative to the belt or relative to fixed points X and Y?
 
  • #10
kuruman said:
How can there be a "round trip" when the direction of the speed is "the same" throughout?
The conveyor belt moves always in the same direction, so presumably the car does not.
 
  • #11
This is a math problem as far as I can tell (sorry if I'm being captain obvious). The car travels speed ##v## relative to the belt, and when it gets to ##Y## it immediately reverses direction without changing speed and travels back to ##X##.
 
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  • #12
Hi @Tonyapplepan. Welcome to PF.

If you haven't yet read the Forum guidelines (https://www.physicsforums.com/threads/homework-help-guidelines-for-students-and-helpers.686781/), note that you are required to show evidence of your own thinking/work. We don't simply give the answer; you'll get guidance to help you work out the answer for yourself.

If you are not yet clear, the question is asking you to say which one is bigger, t₁ or t₂ - or if they are equal (or, less likely, if there is insufficient information to decide). And to explain your reasoning.

So you need to make some initial attempt and post your work here. Hint: If you call the speed of the belt 'u', the speed of the car relative to the belt 'v', and the distance between X and Y 'd', can you work out formulae for t₁ and t₂?
 
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FAQ: Questions about speed and motion of a toy car on a conveyor belt

How does the speed of the conveyor belt affect the motion of the toy car?

The speed of the conveyor belt directly affects the relative motion of the toy car. If the toy car is stationary relative to the conveyor belt, it will move at the same speed as the conveyor belt. If the toy car is moving in the same direction as the conveyor belt, its speed relative to the ground will be the sum of its speed relative to the conveyor belt and the speed of the conveyor belt. Conversely, if it is moving in the opposite direction, the speeds will subtract.

What happens if the toy car's wheels are free to spin without friction?

If the toy car's wheels are free to spin without friction, the car will not move relative to the conveyor belt. Instead, the wheels will simply spin in place, and the car will remain stationary relative to the ground. This is because there is no frictional force to propel the car forward or backward.

How does friction between the toy car's wheels and the conveyor belt affect its motion?

Friction between the toy car's wheels and the conveyor belt is crucial for the car's motion. If there is sufficient friction, the car will be propelled forward or backward depending on the direction of the conveyor belt's movement and the car's own propulsion mechanism. Without enough friction, the wheels may slip, and the car's motion will not be as intended.

Can the toy car move faster than the conveyor belt?

Yes, the toy car can move faster than the conveyor belt if it has its own propulsion system, such as a motor, that allows it to exceed the speed of the conveyor belt. In this case, the car's speed relative to the ground will be the sum of its own speed and the speed of the conveyor belt if moving in the same direction, or the difference if moving in the opposite direction.

What is the effect of the conveyor belt's direction on the toy car's motion?

The direction of the conveyor belt's movement will influence the toy car's relative speed and direction. If the conveyor belt moves in the same direction as the toy car, the car's speed relative to the ground will increase. If the conveyor belt moves in the opposite direction, the car's speed relative to the ground will decrease. The net effect depends on the relative speeds of the car and the conveyor belt.

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