Quick acceleration word problem

In summary, an electron with an initial speed of 3.0 x10^5 m/s undergoes an acceleration of 8.0 x 10^14 m/s/s. Using the equation Rate x Time = Distance, it can be determined that it will take 3x10^18 seconds to reach a speed of 5.4 x 10^5 m/s. To find the distance traveled, one of the equations for motion with a constant acceleration can be used.
  • #1
joe215
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Homework Statement


An electron has an initial speed of 3.0 x10^5 m/s. It undergoes an acceleration of 8.0 x 10^14 m/s/s. (a) How long will it take to reach a speed of 5.4 x 10^5 m/s? (b) How far will it have traveled in this time?


Homework Equations



Rate x Time= Distance



The Attempt at a Solution



A. R x T= D

(8.0 x 10^14 m/s/s)(T)=(5.4 x 10^5 m/s)-(3.0 x10^5 m/s)

T= 3x10^18 seconds

B. How do you find the distance traveled? This is stumping me for some reason.


Thanks!
 
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  • #2
Assuming the magnitude of acceleration is correct, that's a huge acceleration.

The T should be quite small.

What is the relationship between the change in velocity, acceleration and time?
 
  • #3
Joe has the correct relation, even if the terminology is a bit odd ("Distance" is really change in velocity, "Rate" is acceleration). He just needs to carefully redo the arithmetic given by that relation.

Part B: your textbook has 3 or 4 equations for motion with a constant acceleration. Look over them, and choose one which can be solved for distance using the given information.
 

FAQ: Quick acceleration word problem

How do you solve a quick acceleration word problem?

To solve a quick acceleration word problem, you first need to identify the given information and the unknown variable. Then, use the formula for acceleration (a = (vf - vi)/t) to plug in the values and solve for the unknown variable. Make sure to pay attention to units and use the correct units in your final answer.

What is acceleration and how is it related to velocity?

Acceleration is the rate at which an object's velocity changes over time. It is a vector quantity, meaning it has both magnitude and direction. Acceleration is directly related to velocity, as a change in acceleration will result in a change in velocity. The greater the acceleration, the greater the change in velocity over a given period of time.

Can you provide an example of a quick acceleration word problem?

Sure, here is an example: A car starts from rest and reaches a velocity of 30 m/s in 5 seconds. What is the acceleration of the car? To solve this problem, we use the formula a = (vf - vi)/t and plug in the given values, which gives us a = (30 m/s - 0 m/s)/5 s = 6 m/s².

How does mass affect acceleration?

The mass of an object does not directly affect its acceleration. However, a greater mass will require a greater force to accelerate at the same rate as an object with a smaller mass. This is described by Newton's second law of motion: F = ma, where F is the force applied, m is the mass, and a is the acceleration.

Are there any common mistakes to avoid when solving quick acceleration word problems?

Yes, one common mistake is not paying attention to units. Make sure to use the correct units throughout the problem and include units in your final answer. Another mistake is using the wrong formula. Make sure to use the formula for acceleration (a = (vf - vi)/t) and not confuse it with the formula for average speed (s = d/t).

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