- #1
specwarop
- 11
- 0
Gday,
Just a quick one regarding integration.
The rules at the back of my calculus book states that the Integral of
tan(u) du = In(|sec u|) + C
However, my calculators and Wolfram all give me the answer as being
tan(u) du = -In(|cos u|) + C
Which one is correct, which do I believe?
Regards
Just a quick one regarding integration.
The rules at the back of my calculus book states that the Integral of
tan(u) du = In(|sec u|) + C
However, my calculators and Wolfram all give me the answer as being
tan(u) du = -In(|cos u|) + C
Which one is correct, which do I believe?
Regards