- #1
MathWarrior
- 268
- 5
I have solved this equation but I am just not quite sure why this final result is the way it is.
[itex]\frac{2e^{t}+C}{e^{t}} = 2e^{-t} + C[/itex]
Why is it [itex]e^{-t}[/itex] when its simplified ?
[itex]\frac{2e^{t}+C}{e^{t}} = 2e^{-t} + C[/itex]
Why is it [itex]e^{-t}[/itex] when its simplified ?